Question

The dimensions of rectangle A are four times the dimensions of rectangle B. The area of rectangle B is 162 cm2. What is the area of rectangle A?

Answer 1

Answer:

2,592 square cm.

Step-by-step explanation:

It is given that the dimensions of rectangle A are four times the dimensions of rectangle B.

Let dimensions of rectangle B are l×b.

So, the dimensions of rectangle A are 4l×4b.

Area of rectangle is

$Area=length\times width$

Area of rectangle B is

$A_B=l\times w$

The area of rectangle B is 162 square cm.

$A_B=l\times w=162$

Area of rectangle A is

$A_A=4l\times 4w=16(l\times w)=16(162)=2592$

Therefore, the area of rectangle A is 2,592 square cm.