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Vesnalui [34]
3 years ago
7

What is the range of the function below: Let a(x)=x+2 such that x is a positive integer.

Mathematics
2 answers:
jek_recluse [69]3 years ago
4 0
The domain of a(x) is I, positive integers (stated in the question)
the range of a(x) is all positive integers >2
liubo4ka [24]3 years ago
3 0
So all positive integers is the domain (the number  you can use)

and the range (the numbers you get when you put the numbers in the domain in) is all positive integers more than 2
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Select all equations that match the solution for this equation: 5(x - 12) = 20
mixer [17]

Answer:

The answer is x=16 so whatever the equations should look like it should be this:

Step-by-step explanation: 5(x-12)=20 5x-60=20 add 60 to 20 and get 5x=80 x=16

5 0
3 years ago
A web music store offers two versions of a popular song. The size of the standard version is 2.3 megabytes (MB). The size of the
Effectus [21]

answer

240 standard versions

set up equations

s = number of standard versions

h = number of high quality versions

the total size of all standard versions would be 2.3s since each standard version is 2.3 MB

the total size of all high quality versions would be 4.4h since each standard version is 4.4 MB

add them together to get the total size (2664 MB) of all versions

2664 = 2.3s + 4.4h

since the high quality version was downloaded twice as often as the standard, we can say that

h = 2s

substitute h into equation and solve

2664 = 2.3s + 4.4h

h = 2s

2664 = 2.3s + 4.4(2s)

2664 = 2.3s + 8.8s

2664 = 11.1s

s = 2664/11.1

s = 240

7 0
3 years ago
Finish this 1-5 all of it
horrorfan [7]
You are lazy... do it on your own.
3 0
3 years ago
The question is below​
Cloud [144]

Answer:

See below.

Step-by-step explanation:

a.

The first figure has 1 square. The second figure has a column of 2 squares added to the left. The third figure has a column of 3 squares added to the left. Each new figure has a column of squares added to the left containing the same number of squares as the number of the figure.

b.

Figure 10 has 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 = 55 squares.

c.

The formula for adding n positive integers starting at 1 is:

1 + 2 + 3 + ... + n = n(n + 1)/2

For figure 55, n = 55.

n(n + 1)/2 = 55(56)/2 = 1540

d.

Let's use the formula set equal to 190 and solve for n. If n is an integer, then we can.

n(n + 1)/2 = 190

n(n + 1) = 380

We know that 380 = 19 * 20, so n = 19.

Answer: yes

e.

Use the formula above,

S = n(n + 1)/2, where S is the sum.

f.

n(n + 1) = 1478

38 * 39 = 1482

37 * 38 = 1406

3 0
3 years ago
Find all the missing elements:
mrs_skeptik [129]

Answer:

C = 20°

.....................

4 0
2 years ago
Read 2 more answers
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