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4 years ago

Which of the following numbers will produce a rational number when multiplied by 1/5?

Mathematics

1 answer:

Anuta_ua [19.1K]4 years ago

3 0

D: -2/3
That's your answer...
Hope this helps! Please give me a 5-rate and a thanks! (and brainliest) thanks!

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The ratio of men to women to children at a concert was 3:5:2. If there were 360 more adults than children, how many people were

Vladimir79 [104]

The question narrows the groups down from 3 groups with men, women and children to 2 groups with adults and children. Combine the ratios of the men and the women to children to create this new ratio: (3+5):2 = 8:2. You can then simplify it to 4:1.

Let x be the number of children.

$4:1 = (x+360) : x$

Cross-multiply the two ratios to get the expression below, simplify and solve for x:

$x + 360 = 4x$
$360 = 4x - x$
$360 = 3x$
$x = \frac{360}{3}$
$x = 120$

Since there are 120 children, simply add the number of adults (360 more than this value as mentioned before) and you have your final answer:

$total = 120 + (360 + 120)$
$total = 600$

Hope this helped :)

7 0

3 years ago

Temperature transducers of a certain type are shipped in batches of 50. A sample of 60 batches was selected, and the number of t

algol [13]

Answer:

(a) See attachment for table

(b) $Atmost\ 6 = 21.667\%$

(d) $At\ least\ 6 = 78.333\%$

Step-by-step explanation:

Given

The data (in the question)

Solving (a): Frequency and Relative frequencies of each data

The range of the data is 0 to 8. So the frequency of each is the number of times each of 0 - 8 occurs.

This is tabulated below:

$\begin{array}{ccc}x & {Frequency} & {Relative\ Frequency} & {0} & {7} & {11.667\%} &{1}& {13} & {21.667\%} & {2} & {13} & {21.667\%} & {3} & {14} &{23.333\%} & {4} & {5} & {8.333\%} & {5} &{3} &{5.000\%} &{6} &{2} & {3.333\%} & {7} & {2} & {3.333\%} & {8} & {1} & {1.667\%} \ \end{array}$

$Total\ \ \ 60$

The relative frequency is calculated as:

$Relative\ Frequency = \frac{Frequency}{Total\ Frequency} * 100\%$

For instance: When x = 0:

$Relative\ Frequency = \frac{7}{60} * 100\%$

$Relative\ Frequency = \frac{700}{60} * \%$

$Relative\ Frequency = 11.667 \%$

Solving (b): Proportion that have at most 6.

Here, we consider frequencies of 0 to 6.

This is represented as thus:

$\begin{array}{ccc}x & {Frequency} & {Relative\ Frequency} & {4} & {5} & {8.333\%} & {5} &{3} &{5.000\%} &{6} &{2} & {3.333\%} & {7} & {2} & {3.333\%} & {8} & {1} & {1.667\%} \ \end{array}$

Add up the relative frequencies to get the proportion

$Atmost\ 6 = 8.333\% + 5.000\% + 3.333\% + 3.333\% + 1.667\%$

$Atmost\ 6 = 21.667\%$

Solving (c): Proportion that have at fewer than 6.

Here, we consider frequencies of 0 to 5.

This is represented as thus:

$\begin{array}{ccc}x & {Frequency} & {Relative\ Frequency} & {4} & {5} & {8.333\%} & {5} &{3} &{5.000\%} &{6} &{2} & {3.333\%} & {7} & {2} & {3.333\%} & {8} & {1} & {1.667\%} \ \end{array}$

Add up the relative frequencies to get the proportion

$Less\ than\ 6 = 8.333\% + 5.000\% + 3.333\% + 3.333\% + 1.667\%$