Answer:
the y intercept at this point is 7
Step-by-step explanation:
hope this helps comment if not
The numbers are 105 and 50
<em><u>Solution:</u></em>
Let "x" be the first number
Let "y' be the second number
Twice a number plus twice a second number is 310
Therefore,
twice of x + twice of y = 310
2x + 2y = 310 ---------- eqn 1
The difference between the numbers is 55
x - y = 55 -------- eqn 2
<em><u>Let us solve eqn 1 and eqn 2</u></em>
From eqn 2,
x = 55 + y ------ eqn 3
<em><u>Substitute eqn 3 in eqn 1</u></em>
2(55 + y) + 2y = 310
110 + 2y + 2y = 310
4y = 310 - 110
4y = 200
<h3>y = 50</h3>
<em><u>Substitute y = 50 in eqn 3</u></em>
x = 55 + 50
<h3>x = 105</h3>
Thus the numbers are 105 and 50
Answer:
C, D and E
Step-by-step explanation:
Assuming
f(x) = √(9−8x)
and the options are:
A. p(x) = √(-8x) and q(x)=9+x
B. p(x) = √(9+x) and q(x)=8x
C. p(x) = √(-x) and q(x)=8x−9
D. p(x)=√(9−x) and q(x)=8x
E. p(x)=√x and q(x)=9−8x
F. p(x)=9−8x and q(x)=√x
G. All of the above
H. None of the above
Substituting in f(x)=p(q(x)) we get:
A. √(-8(9+x)) = √(-72 - 8x)
B. √(9+(8x)) = √(9+8x)
C. √(-(8x−9
)) = √(-8x + 9)
D. √(9−(8x)) = √(9−8x)
E. √(9−8x
)
F. 9−8(√x
) = 9 - 8√x
The real definition is worth a large deal of money so A
For me, I know that this answer would be greater than 10 because for a fact, 621 and 59 aren't just perfect multiples of 10. But I don't know, because all humans don't really think alike. So, your teacher might say this doesn't work. Then in that case, I am very sorry. :0
But in any case, I hope this helps and have a good night! :D