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alexandr402 [8]
3 years ago
5

Write the declaration statement for a two-dimensional array X of integers with five rows and five columns that accepts 25 intege

rs from the user.
Computers and Technology
1 answer:
madreJ [45]3 years ago
5 0

Answer:

int[ ][ ] X = new int[5][5];

It can also be declared and initialized this way:

  int[][] X = {

               {1,2,3,6,8},

               {4, 5, 6, 9},

               {7,5,6,8,9},

               {8,5,8,8,9},

               {10,2,6,8,11},

       };

Explanation:

Above is a declaration of a two-dimensional array that can hold 5*5=25 int values. A java program is given below:

public class JavaTwoD{

   public static void main(String args[ ]) {

       // creating the 5X5 array

       int[ ][ ] X = new int[5][5];

       // looping through the array to add elements

       for (int i = 0; i < X.length; i++) {

           for (int j = 0; j < X[i].length; j++) {

               X[i][j] = i * j;

           }

       }

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prohojiy [21]

Answer:

The correct option is C: For objects to communicate effectively with one another, each must know how the other object is implemented.

Explanation:

For effective communication of objects with each other, there is no need for each object to know how the other object is implemented. The rules for communication are already defined, and hence you do not have to know, as details of implementation are hidden. Hence the only false statement from the options is C.

5 0
3 years ago
Which composer below was not part of the classical period? <br> A. Beethoven B. Bach<br> C. Mozart
castortr0y [4]

Explanation:

B. Bach

Thanks for your point

3 0
3 years ago
Difference between academic library and school Library
GREYUIT [131]
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8 0
3 years ago
Create a function that will perform linear interpolation from a set of measured data stored in a list or array. The function sho
wel

Answer:

This question is incomplete, here is the complete question:

Python

a) You should create a function that will perform linear interpolation from a set of measured data. The function should take as input a list of values at which samples were taken, and then another list giving the measurements (you can assume each measurement is a single value) at those values. It should also take in a query value, and should give the best estimate it can of the value at that query. Be sure to handle values that are outside of the range, by extrapolating. You should write a program that allows you to test your function by reading the lists from a file where each line of the file is a pair of numbers separated by spaces: the value where the sample was taken, and the measurement at that value. Your program should ask the user for the name of the file and for a query value. Important: The two lists will correspond to each other: i.e. for the i-th value in the first list, the measurement will be the i-th element of the second list (these are called parallel lists or arrays). But, you should not assume that the input values are in increasing/decreasing order. That is, the values in the first list can be in any random ordering, not necessarily from smallest to largest or largest to smallest. You will have to account for this in your program, and there is more than one way to do so. You should discuss what options you can think of to handle the data arriving in any order like that, and decide what you think the best option for handling it is.

Explanation:

from __future__ import division

from cStringIO import StringIO

import numpy as np

from scipy.interpolate import RectBivariateSpline

np.set_printoptions( 1, threshold=100, edgeitems=10, suppress=True )

   # a file inline, for testing --

myfile = StringIO( """

# T P1 P2 P3 P4

0,   80,100,150,200

75, 400,405,415,430

100, 450,456,467,483

150, 500,507,519,536

200, 550,558,571,589

""" )

   # file -> numpy array --

   # (all rows must have the same number of columns)

TPU = np.loadtxt( myfile, delimiter="," )

P = TPU[0,1:] # top row

T = TPU[ 1:,0] # left col

U = TPU[1:,1:] # 4 x 4, 400 .. 589

print "T:", T

print "P:", P

print "U:", U

interpolator = RectBivariateSpline( T, P, U, kx=1, ky=1 ) # 1 bilinear, 3 spline

   # try some t, p --

for t, p in (

   (75, 80),

   (75, 200),

   (87.5, 90),

   (200, 80),

   (200, 90),

   ):

   u = interpolator( t, p )

   print "t %5.1f p %5.1f -> u %5.1f" % (t, p, u)

8 0
3 years ago
Def pig_latin(word): """ ------------------------------------------------------- Converts a word to Pig Latin. The conversion is
Virty [35]

def pig_latin(word):

   if word[0].lower() in 'aeiou':

       word = word + 'way'

   else:

       t=''

       for x in range(len(word)):

           if word[x].lower() in 'aeiou':

               break

           if word[x].lower() == 'y' and x>0:

               break

           else:

               t+=word[x].lower()

       if word[0].isupper():

           word = word[len(t):]+word[:len(t)].lower()+'ay'

           word = word.title()

       else:

           word = word[len(t):]+word[:len(t)].lower()+'ay'

   return word

word = 'test'

pl = pig_latin(word)

print(pl)

I wrote my code in python 3.8. I hope this helps.

5 0
3 years ago
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