I know filters, so I know it is Saturation.
Answer:
import java.util.*;
public class MyClass {
public static void main(String args[]) {
Scanner input = new Scanner(System.in);
System.out.print("Input a word: ");
String userinput = input.nextLine();
for(int i =0;i<userinput.length();i+=2) {
System.out.print(userinput.charAt(i));
}
}
}
Explanation:
This line prompts user for input
System.out.print("Input a word: ");
This declares a string variable named userinput and also gets input from the user
String userinput = input.nextLine();
The following iterates through every other character of userinput from the first using iteration variable i and i is incremented by 2
for(int i =0;i<userinput.length();i+=2) {
This prints characters at i-th position
System.out.print(userinput.charAt(i));
Cloud-first strategy differ from other approaches as It keeps all the services performed by legacy systems while moving to the Cloud in a staggered approach.
<h3>What is a cloud first strategy?</h3>
The change of cloud computing has brought about “cloud-first” strategy.
This is known to be a way to computing that tells that a firm should look first to cloud solutions when creating new processes or taking in old processes before taking in non-cloud-based solutions.
Note that Cloud-first strategy differ from other approaches as It keeps all the services performed by legacy systems while moving to the Cloud in a staggered approach.
See options below
it enables an organization to completely move to the cloud without infrastructure or support requirement
it keeps all the services performed by legacy systems while moving to the cloud in a staggered approach.
it partners technology with multiple other disciplines for comprehensive business transformation.
it uses artificial intelligence to automate all business processes and completely eliminate human error.
Learn more about cloud from
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Answer:
#include <iostream>
using namespace std;
class Digits
{
public:
int num;
int read() //method to read num from user
{
cout<<"Enter number(>0)\n";
cin>>num;
return num;
}
int digit_count(int num) //method to count number of digits of num
{
int count=0;
while(num>0) //loop till num>0
{
num/=10;
count++; //counter which counts number of digits
}
return count;
}
int countDigits(int num) //method to return remainder
{
int c=digit_count(num); //calls method inside method
return num%c;
}
};
int main()
{
Digits d; //object of class Digits is created
int number=d.read(); //num is read from user
cout<<"\nRemainder is : "<<d.countDigits(number); //used to find remainder
return 0;
}
Output :
Enter number(>0)
343
Remainder is : 1
Explanation:
As program is missing to find errors , a logically write program is written to find the remainder when a number is divided by its number of digits. A class Digits is constructed which has public variable num and methods read(), digit_count(), countDigits().
- read() - This method reads value of num from the user and return num.
- digit_count() - This method takes a integer as parameter and counts the number of digits of a number passed as argument. while loop is used to increement the counter until num<0. This returns the value of count.
- countDigits() - This method takes a integer as a parameter and returns remainder when the argument is divided by number of digits of argument. Number of digits is calculated by using method digit_count().
At last in main method , object of Digits class is created and its methods are used to find the output.
Answer:
file_name = 'orders.txt'
file_obj = open( file_name, 'r' )
lines = file_obj.read()
print(lines.upper(), end = '')
Explanation:
- Define the name of the file
.
- Use the built-in open function to open the file in read mode
.
- Use the built-in read function to read the file and assign this to lines variable.
- Finally display the lines by converting them to capital alphabets by using the built-in upper() function.