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Elanso [62]
3 years ago
7

Write an equation of the line that is parallel to 3x + 9y = 7 and passes through the point (6, 4).

Mathematics
1 answer:
Ber [7]3 years ago
4 0
First, rearrange the equation to standard line format
3x + 9y = 7
9y = -3x + 7
y = -3/9x + 7/9
y = -1/3x + 7/9

now we know the slope of the line (both the existing and the new parallel one, since they both have the same slope)

y = -1/3x + b

plug in the new point in and solve for b

4 = -1/3(6) + b
4 = -2 + b
b = 6

y = -1/3x + 6 is the equation for the parallel line
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Kiran says that a solution to the equation x+4=20 must also be a solution to the equation 5(x+4)=100 Write a convincing explanat
Helen [10]

Answer:

x+4=20 is a solution to 5(x+4)=100.

Step-by-step explanation:

Following PEMDAS, divide 5 from both sides of the equation 5(x+4)=100, and you have x+4=20 remaining.

This means that both equations have the same solution.

8 0
3 years ago
I'll mark as brainliest if it lets me;-;<br>please answer B. &amp; C. with solution:)​
san4es73 [151]

Answer:

B. AC = 22, BC = 22, AB = 44

C. AC = 30, BC = 30, AB = 60

Step-by-step explanation:

B.

radius \: \overline {OR} \perp chord \: \overline {AB} at C. (given)

\therefore AC = BC (perpendicular dropped from the center of the circle to the chord bisects the chord)

\therefore 2x - 6 = x + 8

\therefore 2x - x= 6 + 8

\therefore x= 14

AC = 2x-6=2(14)-6=28-6= 22

BC= x + 8=14 + 8= 22

AB = AC + BC = 22 + 22 = 44

C.

radius \: \overline {OR} \perp chord \: \overline {AB} at C. (given)

\therefore BC = AC (perpendicular dropped from the center of the circle to the chord bisects the chord)

\therefore 7x-5=4x+10

\therefore 7x - 4x= 5 + 10

\therefore 3x= 15

\therefore x= \frac{15}{3}

\therefore x= 5

AC = 4x+10=4(5)+10=20+10= 30

BC= 7x - 5=7(5)-5=35-5= 30

AB = AC + BC = 30 + 30 = 60

7 0
2 years ago
Determine the equation for the line of best fit to represent the data.
Jlenok [28]

Answer:

d

Step-by-step explanation:

8 0
2 years ago
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denis23 [38]

Answer:      B Or A

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Is floor(x) periodic?
diamong [38]

If you look at the graph of y = floor(x), you'll see a stairstep pattern that climbs up as you read from left to right. There are no vertical components to the graph. There are only horizontal components.

The graph is not periodic because the y values do not repeat themselves after a certain x value is passed. For instance, start at x = 0 and go to x = 3. You'll see the y values dont repeat themselves as if a sine function would. If you wanted the function to be periodic, the steps would have to go downhill at some point; however, this does not happen.

Conclusion: The function floor(x) is <u>not</u> periodic.

4 0
3 years ago
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