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Elanso [62]
3 years ago
7

Write an equation of the line that is parallel to 3x + 9y = 7 and passes through the point (6, 4).

Mathematics
1 answer:
Ber [7]3 years ago
4 0
First, rearrange the equation to standard line format
3x + 9y = 7
9y = -3x + 7
y = -3/9x + 7/9
y = -1/3x + 7/9

now we know the slope of the line (both the existing and the new parallel one, since they both have the same slope)

y = -1/3x + b

plug in the new point in and solve for b

4 = -1/3(6) + b
4 = -2 + b
b = 6

y = -1/3x + 6 is the equation for the parallel line
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user100 [1]

Answer:

x = -7

Step-by-step explanation:

Simplifying

5x + 130 = 8x + 151

Reorder the terms:

130 + 5x = 8x + 151

Reorder the terms:

130 + 5x = 151 + 8x

Solving

130 + 5x = 151 + 8x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-8x' to each side of the equation.

130 + 5x + -8x = 151 + 8x + -8x

Combine like terms: 5x + -8x = -3x

130 + -3x = 151 + 8x + -8x

Combine like terms: 8x + -8x = 0

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130 + -3x = 151

Add '-130' to each side of the equation.

130 + -130 + -3x = 151 + -130

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