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velikii [3]
3 years ago
15

Please help. I think I know but I'd like to have it confirmed.

Mathematics
1 answer:
V125BC [204]3 years ago
4 0
Part 1
40 \times 10.5 = 402
Part 2
40 \times 10.5 + 5 \times 1.5 \times 10.5 \\ = 402 + 78.75 \\ = 480.75
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3 years ago
The amounts a soft drink machine is designed to dispense for each drink are normally distributed, with a mean of 12.1 fluid ounc
Ludmilka [50]

Answer:

\mu = 12.1\\\sigma = 0.3

a) Find the probability that the drink is less than 11.9 fluid ounces

We are supposed to find P(x<11.9)

x= 11.9

We will use z score formula :

z=\frac{x-\mu}{\sigma}

z=\frac{11.9-12.1}{0.3}

z=-0.67

Refer the z table

So, P(z<-0.67) = 0.2514

Hence the probability that the drink is less than 11.9 fluid ounces is 0.2514

b)Find the probability that the drink is between 11.6 and 11.9 fluid ounces

x= 11.6

We will use z score formula :

z=\frac{x-\mu}{\sigma}

z=\frac{11.6-12.1}{0.3}

z=-1.67

x= 11.9

We will use z score formula :

z=\frac{x-\mu}{\sigma}

z=\frac{11.9-12.1}{0.3}

z=-0.67

We are supposed to find P(11.6<x<11.9)

So, P(11.6<x<11.9)= P(x<11.9)-P(x<11.6)

P(-1.67<z<-0.67)= P(z<-0.67)-P(z<-1.67)

Refer the z table

P(-1.67<z<-0.67)= P(z<-0.67)-P(z<-1.67)

P(-1.67<z<-0.67)= 0.2514-0.0475

P(-1.67<z<-0.67)= 0.2039

So, the probability that the drink is between 11.6 and 11.9 fluid ounces is 0.2039.

c)Find the probability that the drink is more than 12.6 fluid ounces

We are supposed to find P(x>12.6)

x= 12.6

We will use z score formula :

z=\frac{x-\mu}{\sigma}

z=\frac{12.6-12.1}{0.3}

z=1.67

Refer the z table

P(x>12.6)=1-P(x<12.6)

P(z>1.67)=1-P(z<1.67)

P(z>1.67)=1-0.9525

P(z>1.67)=0.0475

Hence  the probability that the drink is more than 12.6 fluid ounces is 0.0475

d) Is the drink containing more than 12.6 fluid ounces an unusual event?

Since p value is less than  alpha (0.05)

Answer = No, because the probability that a drink containing more than 12.6 fluid ounces is less than 0.05, this event is not unusual.

3 0
3 years ago
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