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Mama L [17]
3 years ago
8

a ferry is traveling at a constant speed back to the dock, as shown in the graph. which function represents the relationship bet

ween the distance from the ferry to the dock in miles, y, and the time that the ferry has been traveling toward the dock in hours, x?
Mathematics
1 answer:
horsena [70]3 years ago
6 0

Answer: y = -35x + 105

Step-by-step explanation:

The graph represents a function that is between hours and miles and to determine the equation which belong to this graph, we need to find the slope first by using two points from the graph which are (0, 105) and (3, 0).

The definition of slope is

m = (y2 - y1)/(x2 - x1)

= (0-105)/3-0

= -105/3

= -35

The slope is -35 and remember that the slope is the coefficient of the variable x. Therefore, the answer is:

y = -35x + 105

You might be interested in
Write a function in any form that would match the graph shown below
ella [17]

Answers:

  • Vertex form:  y = -2(x-1)^2 + 8
  • Standard form: y = -2x^2 + 4x + 6

Pick whichever form you prefer.

=============================================================

Explanation:

The vertex is the highest point in this case, which is located at (1,8).

In general, the vertex is (h,k). So we have h = 1 and k = 8.

One root of this parabola is (-1,0). So we'll plug x = -1 and y = 0 in as well. As an alternative, you can go for (x,y) = (3,0) instead.

Plug those four values mentioned into the equation below. Solve for 'a'.

y = a(x-h)^2 + k

0 = a(-1-1)^2+8

0 = a(-2)^2+8

0 = 4a+8

4a+8 = 0

4a = -8

a = -8/4

a = -2

The vertex form of this parabola is   y = -2(x-1)^2+8

Expanding that out gets us the following

y = -2(x-1)^2+8

y = -2(x^2-2x+1)+8

y = -2x^2+4x-2+8

y = -2x^2+4x+6 .... equation in standard form

7 0
2 years ago
Ds
Aleksandr [31]

Answer:

so the answer is I don't know

5 0
3 years ago
Pls help me with trig :)
trapecia [35]

Answer:

Step-by-step explanation:

let ∠GEF=x

then ∠GFE=90-x

\frac{GH}{EH}=tan x\\GH=EH~ tan x\\or~ GH=a ~tan x=6 tan x\\\frac{GH}{FH}=tan (90-x)=cot x\\GH=FH*cot x\\GH=b*cot x=27 cot x\\6 tan x=27 cotx\\\frac{tan x}{cot x}=\frac{27}{6}\\tan ^2 x=\frac{27}{6}=\frac{9}{2}\\sec^2x-tan^2x=1\\sec^2 x=1+tan ^2x=1+\frac{9}{2}=\frac{11}{2}\\\frac{EG}{EH}=sec x\\ EG=EH sec x=a sec x= 6 sec x=6\sqrt{\frac{11}{2} } =3\sqrt{22} \approx 14.07

4 0
3 years ago
Question 18: Please help, I'm not sure but I think the answer is either C or D.
Ad libitum [116K]

Answer:I think it is C

Step-by-step explanation:

3 0
3 years ago
Ella has gold,silver,and copper wire for stringing beads.she has1 1\2ft.of gold wire,2 1\3ft.of silver wire,and3 3\4ft.of copper
Oksana_A [137]
Ella would have 65/8ft wire all together.
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