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pogonyaev
3 years ago
13

Abigail needs 19th inches of copper for an experiment. the wire is sold by the centimeter given that 1 inch equals 2.54 cm how m

any centimeters of wire does Abigail need?
Mathematics
1 answer:
Veseljchak [2.6K]3 years ago
8 0

Abigail needs 19th inches of copper for an experiment. the wire is sold by the centimeter given that 1 inch equals 2.54 cm 105.26 centimeters of wire does Abigail need .

<u>Step-by-step explanation:</u>

Here we have , Abigail needs 19th inches of copper for an experiment. the wire is sold by the centimeter given that 1 inch equals 2.54 cm  . We need to find out that how many centimeters of wire does Abigail need .Let's find out:

It's given and we also know that 1 inch is equivalent to 2.54 cm i.e.

⇒ 1 inch = 2.54cm

So , let's find 19 inch have how many cm's :

⇒ 19(2.54)cm

⇒ 105.26cm

19 inch is equivalent to 105.26 cm or , 19inch = 105.26 cm . Therefore, Abigail needs 19th inches of copper for an experiment. the wire is sold by the centimeter given that 1 inch equals 2.54 cm 105.26 centimeters of wire does Abigail need .

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Been a while since I've done synthetic division.

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p(x) = 2x⁴ - 3x³ - 6x² + 5x + 6

possible rational roots have factors of 6 in the numerator and of 2 in the denominator.  We'll only worry about negative numerators.

Factors of six: 1,2,3,6, and we don't forget -1,-2,-3,-6

Factors of 2: 1,2

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(dividing by 1:) 1,-1,2,-2,3,-3,6,-6

(dividing by 2:) 1/2, -1/2  (2/2=1 is a duplicate, don't have to repeat it), 3/2, -3/2

Possible rational roots: 1,-1,2,-2,3,-3,6,-6, 1/2, -1/2, 3/2, -3/2

Synthetic division, trying x=1,

   1 | 2  -3  -6  5  6

             2  -1  -7  -2

       2    -1  -7  -2  4

Got a remainder of 4, so 1 isn't a root;

Trying x=-1  

-1 | 2  -3  -6  5  6

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Same set of rational roots on the cubic, we continue with x=2

2 | 2 -5 -1 6

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Another zero remainder, x=2 is a root.  We're left with 2x² - x - 3 = 0, which factors as

(2x - 3)(x + 1) = 0

That's a second factor of x+1.  Our final factorization is

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Fourth degree with a positive leading coefficient so goes to +infinity at both ends.  Double zero at x=-1, so it's tangent there, just touching the x axis, then down through x=3/2 and up through x=2.  

I'll leave the actually sketching and the other two polynomials to you -- that took some time.

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