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deff fn [24]
2 years ago
6

Question 2 of 10

Mathematics
1 answer:
KIM [24]2 years ago
3 0

hi my name is afsshenn I am stealing your points hahaha

You might be interested in
The number 6 is a solution to which of the following inequalities?
Paladinen [302]

Answer:

21 + x < 28

Step-by-step explanation:

27 is in fact greater than 28 if you where to input 6 into the x spot, this is the only one that's a true expression.

8 0
3 years ago
The distance between Anubhav’s school and his house is 45 km. He started from his house for school at 7:00 am and covered 30 km
8_murik_8 [283]

Answer:

45 km/h

Step-by-step explanation:

In the first part of the trip, he already covered 30 km so we can subtract that from the total distance

45 - 30 = 15

This means he has 15 km to go

He also took an hour, or 60 minutes, to get to school. We subtract the time spent of the first part and time spent talking to a friend from the 60 minutes

60 - 35 = 25

25 - 5 = 20

He took 20 minutes to cover the second part of the journey

Speed = distance/time

15/20 = 0.75

He covered 0.75 km per MINUTE

to find it in km/h, we just multiply the number by 60

0.75 x 60 = 45

6 0
3 years ago
Read 2 more answers
100 POINTS, WILL MARK BRAINLIEST! If h(x) = f[f(x)] use the table of values for f and f ′ to find the value of h ′(1).
victus00 [196]

Answer:

The value of h^\prime(1)=5

Step-by-step explanation:

Given that  h(x)=f(f(x))

now to find h(x)=f(f(x)) from the given functions f(x) and f'x

let h(x)=f(f(x))

Then put x=1 in above function we get

h(1)=f(f(1))

=f(3) (from the table f(1)=3 and f(3)=6)

Therefore h(1)=6

Now to find h'(1)

Let

h^{\prime}(x)=f^{\prime}(f^\prime(x)) (since  h(x)=f(f(x)) )

put x=1 in above function we get

h^{\prime}(1)=f^{\prime}(f^\prime(1))

=f^{\prime}(2)    (From the table f^\prime(1)=2 and f^\prime(2)=5)

h^{\prime}(1)=5

Therefore h^{\prime}(1)=5

4 0
3 years ago
Read 2 more answers
Consider the function f(x)= x² - 4
Arisa [49]

Answer:

(X+2) (X-2) . This is the final answer

Step-by-step explanation:

Solving f(x) = x^2 - 4

A^2 - B^2 is a special case where the original equation before it was foiled is

(A + B) (A - B) because the middle terms will cancel out when foiled.

This means that the equation can be written as

(X + 2)(X - 2) = 0

Each of these you will then set equal to 0 and then solve

X + 2 = 0, X - 2 = 0

X = -2, 2

I hope this helps you! let me now if its right ok <3 :)

4 0
3 years ago
How many solutions does this linear system have?
ziro4ka [17]

Answer: C is correct, No solution

Step-by-step explanation:

Let’s simplify the second equation,

8x-4y=-20

We can divide the whole equation by 4...

8x/4-4y/4=-20/4

Which becomes....

2x-y=-5

Now let’s move things around to see if it’s the same equation as the one on top...

-y=-2x-5

y=2x+5

Now we need to solve the systems...

y=2x-5

y=2x+5

Since their slopes are both 2 and their y-intercepts are not identical, the answer is no solution. The two lines will continue on without ever crossing because they have the same slope.

4 0
3 years ago
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