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3 years ago

HURRY PLEASE :)!!

1 answer:

8 0

The ratio of the areas is the ratio of the squares of the sides ( which is 10:15 or 2:3) so the answer is
2^2 : 3^2 = 4:9.

The ratio of the perimeters = ratio of corresponding side = 2:3.

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Solve this equation. Leave the answer as an improper fraction. 3x^2 + 2 = 11 - x^2

Nikolay [14]

Answer:

$x = \frac{3}{2}orx=-\frac{3}{2}$

Step-by-step explanation:

The given Equation is

$3x^{2} + 2 = 11-x^{2}$ .................(i)

Adding ( $x^{2} -11$ ) on both sides of (i)

$3x^{2}+2+x^{2}-11 = 11-x^{2}+x^{2}-11$

solving and cancelling out the terms will give

⇒ $4x^{2} -9=0$

⇒ $(2x)^{2} -(3)^{2} = 0$ ...................(ii)

Now we Know that

$(a)^{2} -(b)^{2} = (a-b)(a+b)$

Applying this on equation (ii)

$(2x-3)(2x+3)=0$

This will lead us to

Either 2x-3 =0 .......(iii) or 2x+3=0 ..........(iv)

Solving equation (iii) for value of x

2x - 3 =0

adding 3 on both sides

2x -3 +3 = 0+ 3

2x = 3

Cross multiplying gives

$x=\frac{3}{2}$

Solving equation (iv) for value of x

2x + 3 =0

adding -3 on both sides

2x -3 +3 = 0- 3

2x = -3

Cross multiplying gives

$x=\frac{-3}{2}$

so $x=\frac{3}{2}$ and $x=\frac{-3}{2}$

7 0

3 years ago

Solve using elimination.

dmitriy555 [2]

The process and the answer is shown in the following picture. The five ones are all the same.

8 0

2 years ago

Solve for p.

Marat540 [252]

Hi there

3(p + q) = q
Solve for P

Use the distributive property
(3)(p) + (3)(q) = q
3p + 3q = q
3p = q-3q
3p = -2q
p = -2q/3

The answer is D

If you have any further questions please let me know :)

8 0

3 years ago

Read 2 more answers

What is the solution of StartRoot x minus 4 EndRoot + 5 = 2?

Vlad1618 [11]

Answer:

Step-by-step explanation:

$\sqrt{x-4}+5=2 \\\\\sqrt{x-4}=-3 \\\\x-4=9 \\\\x=13$