I think all solution apply
Answer:
cos(θ) = 3/5
Step-by-step explanation:
We can think of this situation as a triangle rectangle (you can see it in the image below).
Here, we have a triangle rectangle with an angle θ, such that the adjacent cathetus to θ is 3 units long, and the cathetus opposite to θ is 4 units long.
Here we want to find cos(θ).
You should remember:
cos(θ) = (adjacent cathetus)/(hypotenuse)
We already know that the adjacent cathetus is equal to 3.
And for the hypotenuse, we can use the Pythagorean's theorem, which says that the sum of the squares of the cathetus is equal to the square of the hypotenuse, this is:
3^2 + 4^2 = H^2
We can solve this for H, to get:
H = √( 3^2 + 4^2) = √(9 + 16) = √25 = 5
The hypotenuse is 5 units long.
Then we have:
cos(θ) = (adjacent cathetus)/(hypotenuse)
cos(θ) = 3/5
A) One solution: 5x +2y = 0 . . . . (any line with a different slope)
b) Two solutions: not possible
c) No solutions: 5x -2y = 0 . . . . (any different line with the same slope)
d) Infinitely many solutions: 10x -4y = 6 . . . . (any other equation for the same line)
The slope is 3/10, and just graph 2 points ( so like .3,1 and .9,2) and just use Desmos to figure out the line using the y=3/10x+3.64 and just type it in