Write an equation of the line that is perpendicular to 5x + 20y = 10 and passes through the point (8, 3).
1 answer:
Given line ax+by=c and point (h, k), the perpendicular line through (h, k) can be written as
b(x-h) -a(y-k) = 0
In order for this to be in standard form, it must be rearranged somewhat, and any common factors removed.
We can start with
20(x-8) -5(y-3) = 0
4x -32 -y +3 = 0
4x -y = 29
The standard-form equation of the desired line through (8, 3) is
4x -y = 29
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17 (i) 2.85 17 (ii) 28.215. this is most likely the correct answers but I could be wrong
The range is:
[−7,7]
{y|−7≤y≤7}