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3 years ago

Find the domain and range of relation

Mathematics

1 answer:

Svetlanka [38]3 years ago

5 0

Go find ppl who need answers and get more points that’s what I’m doing sorry

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How do you add and subtract polynomials?

bekas [8.4K]

Reverse the sign of each term you are subtracting and then add as usual. Hope this helps!

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3 years ago

Plz halp wil giv brainlyes

LuckyWell [14K]

Answer:

∠F = 36.1°

Step-by-step explanation:

tan(x) = $\frac{O}{A} = \frac{3.5}{4.8}$

x = $tan^{-1} (\frac{3.5}{4.8})$ = 36.1°

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3 years ago

What does -7.8x+1.56 equal?

mars1129 [50]

- 39/25x(5x-1) or -1.56(5x-1)

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3 years ago

How do you construct an inscribed hexagon? explain

lianna [129]

Answer:

<em>Draw a circle of some radius. Divide the central angle (360 deg) into 6 equal parts of 60 each by a protractor. Join the points where the lines dividing the angle meets the circumference of the circle.</em>

Step-by-step explanation:

Six sides have the same length and the angles formed by six intersections of lines are correct. If either side has a length different from any other side, or if any of the angles differs from any other, it is not correct.

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3 years ago

EXAMPLE 5 Find the maximum value of the function f(x, y, z) = x + 2y + 9z on the curve of intersection of the plane x − y + z =

geniusboy [140]

The Lagrangian,

$L(x,y,z,\lambda,\mu)=x+2y+9z-\lambda(x-y+z-1)-\mu(x^2+y^2-1)$

has critical points where its partial derivatives vanish:

$L_x=1-\lambda-2\mu x=0$

$L_y=2+\lambda-2\mu y=0$

$L_z=9-\lambda=0$

$L_\lambda=x-y+z-1=0$

$L_\mu=x^2+y^2-1=0$

$L_z=0$ tells us $\lambda=9$ , so that

$L_x=0\implies-8-2\mu x=0\implies x=-\dfrac4\mu$

$L_y=0\implies11-2\mu y=0\implies y=\dfrac{11}{2\mu}$

Then with $L_\mu=0$ , we get

$x^2+y^2=\dfrac{16}{\mu^2}+\dfrac{121}{4\mu^2}=1\implies\mu=\pm\dfrac{\sqrt{185}}2$

and $L_\lambda=0$ tells us

$x-y+z=-\dfrac4\mu-\dfrac{11}{2\mu}+z=1\implies z=1+\dfrac{19}{2\mu}$

Then there are two critical points, $\left(\pm\frac8{\sqrt{185}},\mp\frac{11}{\sqrt{185}},1\pm\frac{19}{\sqrt{185}}\right)$ . The critical point with the negative $x$ -coordinates gives the maximum value, $9+\sqrt{185}$ .

8 0

4 years ago