The mode of a set of numbers is the number that occurs the most.
The numbers in this set are as follows,
26, 17, 9, 12, 18, 21, 9, 14, 18, 23, 15, 7, 20, 18, 17, and 12
26 I
17 II
9 II
12 II
18 III
21 I
14 I
23 I
15 I
7 I
20 I
The number that appears the most is 18!
So the mode of the set of numbers is 18!
A is inbetween 2 and 4
B is inbetween 3 and 4
C is inbetween 4 and 5
D is inbetween 5 and 6
So the correct answer would be A B and C
u = 10.4 and v = 12
Solution:
In the given 2 sides of a triangle are 60°, 60°.
Sum of all the angles of a triangle = 180°
60° + 60° + third angle = 180°
⇒ third angle = 180° – 60° – 60°
⇒ third angle = 60°
All angles are equal, therefore the given triangle is an equilateral triangle.
⇒ All sides are equal in length.
⇒ v = 12
The line drawn from the top angle divides the triangle into two equal parts
and the line is perpendicular.
12 ÷ 2 = 6
Using Pythagoras theorem,
⇒ 
⇒ 
⇒ 
⇒ 
⇒ u = 10.4
Hence, u = 10.4 and v = 12.
1)x+30=40
x=40-30
Answer :x=10
2)30-20+2x=10
10+2x=10
2x=0
Answer: x=0
3)3x-10+13=-2x+28
3x+3=-2x+28
3x+2x+3=28
3x+2x=28-3
5x=28-3
5x=25
x=5
4)13x-23-45=-7x+12
13x-68=-7x+12
13x+7x-68=12
13x+7x=12+68
20x=12+68
20x=80
x=4
5)2(x+4)=10x+24
2x+8=10x+24
2x-10x+8=24
2x-10x=24-8
-8x=24-8
-8x=16
x=-2
6)3(x-5)=1-(2x-4)
3x-15=1-(2x-4)
3x-15=1-2x+4
3x-15=5-2x
3x+2x-15=5
3x+2x=5+15
5x=5+15
5x=20
x=4
7)5x-10=15
5x=15+10
5x=25
x=5
8)x+4=x+6
4=6
no solution
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