So hmm notice the picture below
simply get the area of the segment, and subtract it from the area of the circle, what's left, is the difference
notice your circle, has a radius "r" of 18
Answer: The required width of the park is 3 miles.
Step-by-step explanation: Given that a 5 mile jogging path diagonal divides a rectangular park in half and the park is 4 miles long.
We are to find the width of the park.
As shown in the attached figure below, the diagonal BD divides the rectangle ABCD into two equal parts,
where length DA = 5 miles, BD = 4 miles and AB = width = ?
Since each angle of a rectangle is right-angle, so triangle ABD will be a right-angled triangle.
Using Pythagoras theorem in triangle ABD, we have
Thus, the required width of the park is 3 miles.
Step-by-step explanation:
DCE²+GCH²+X²=180°
40²+27²+X²=180°
x²=2329-180°
x=√2149
x=49//
There are 1000 grams in a kg - so the dog weighs 15,000 grams. Add that to the collar weight (200g) and you get 15,200 grams.
Answer:
breadth = 8, length = 32
Step-by-step explanation:
perimeter = 2 x (length x breadth)
= 2 x ((24 + b) + b))
= 2 x (24 + 2b)
= 48 + 4 b
48 + 4b meters costs rupees 2400
each meter costs rupees 30
so,
30 x (48 + 4b) = 2400
1440 + 120b = 2400
120b = 960
b = 8
the breadth is 8m, the length is 8 + 24 = 32m
