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3 years ago

Ed is 7 years older then ted Ed's age is also 3/2 times ted's age how old are ed and ted

Mathematics

1 answer:

Rasek [7]3 years ago

5 0

Answer:

if i'm right ted is 14 and ed is 21

Step-by-step explanation:

if ed is 7 years older than ted and is 3/2 times eds age, than we have to find out how much dose 2 represent in the equation 3/2 so we know that ed is seven years older than ted. so that means that if the equation 3/2 was 1/2, 1 would represent 7 years. (i hope your following me) so if 1 represents 7 than 2 must represent 14 and that would be the age of ted because in the equation 3/2 the 2 would represent teds age. and if the 2 represents teds age than 3 would be eds age. so 7 x 3 = 21. (this is my first time answering a question so sorry if i'm confusing)

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zloy xaker [14]

Answer:

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Step-by-step explanation:

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2 years ago

The length of a rectangle is 5 less than 3 times its width. The perimeter is

My name is Ann [436]

Answer:

The length is 28 and the width is 11

Step-by-step explanation:

To solve this problem, we can make the width as x.

Since the length is 5 less than 3 times the width, it's going to be 3x - 5

So now we've got the length and width, just need to find the perimeter, which is all the sides added up together. They already gave us the perimeter, so we just have to solve the equation:

2(3x - 5) + 2x = 78

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3x - 5

3 × 11 - 5

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2 years ago

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2 years ago

Assume that females have pulse rates that are normally distributed with a mean of u = 75.0 beats per minute and a standard devia

Elan Coil [88]

Answer:

36.88% probability that her pulse rate is between 69 beats per minute and 81 beats per minute.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 75, \sigma = 12.5$