Answer:
y = 3x/2 + 3
Step-by-step explanation:
First let's solve for y in the given equation
Subtract 3x from both sides
3x - 2y = -10
- 3x - 3x
-2y = -3x - 10
Divde both sides by -2
-2y/-2 = (-3x - 10)/-2
y = 3x/2 + 5
The slop of the parallel equation will have to be 3/2
y = 3x/2 + b
Plug in the given coordinates
4 = 3(2)/2 + b
4 = 1 + b
Subtract 1 from both sides
4 = 1 + b
- 1. - 1
b = 3
y = 3x/2 + 3
Answer:
C
Step-by-step explanation:
Using the law of cosines then cosΘ is the following quotient
cosΘ = 
where a = 5.8, b = 10.5 and c = 10.9
cosΘ = 
= 
=
= 0.21 → C
Answer:
what missing information
Step-by-step explanation:
h(t) is the height of the diver in feet above the water
Now it asks about the time at which diver reaches the water
When diver reaches the water , the height of diver from water should be zero
So we plug h(t) =0
So

divide whole equation by -16

we can now factor the quadratic equation
So we get
(t+4)(t-3) =0
plug each factor equal to zero and solve for t
t+4 =0 and t-3 =0
So t=-4 and t=3
Now time cannot be negative , So t=3
So time = 3 seconds
It takes 3 seconds for the diver to reach the water
D. Although I'm not 100% sure