See the attached picture.
Area of the square base = 5^2 = 25 cm^2
Area of one of the triangular side = 1/2 * 5 * 8 = 20 cm^2 and there are 4 sides
So the surface area of while pyramid = 4 * 20 + 25 = 105 cm^2
Volume of the cone = (1/3) pi r^2 h
= (1/3) pi * 5^2 * 8
= 209.44 ft^2
<span>0.53(3)+5 = 1.59 + 5 = 6.59 when n = 3
</span>0.53(-3)+5 = -1.59 + 5 = 3.41 when n = -3
-28 because using PEMDAS you would do -5x8 which =-40 plus 12 is -28
