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kaheart [24]
3 years ago
14

Mrs. Little creates a boxplot for the test scores on her latest math test. She finds that the interquartile range is 20 points.

What does this mean? A) That the median number of points off was 10. B) That half the students scored 20 points higher. C) That the highest grade was 20 points above the median. D) That the middle 50% of the scores were 20 points apart.

Mathematics
2 answers:
vesna_86 [32]3 years ago
5 0
Hi there!

The interquartile is the upper quartile and lower quartile subtracted.
As the pictures show below.
The interquartile range (IQR) limits the range to the 50% of the values.
So I think the answer is D. That the middle 50% of the scores were 20 points apart.

Hope this helps!

Airida [17]3 years ago
4 0

Answer:

D) That the middle 50% of the scores were 20 points apart.

Step-by-step explanation:

Interquartile range measures the skewness using 50% of the data. It is the difference between the third quartile and the first quartile.

A) this option is incorrect as it does not define the Interquartile range.

B) No, it is the definition of median.

C) No, it does not define the interquartile range.

D) Yes, it is correct answer.

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Find the volume of the solid, please
dsp73

Answer:

V \approx=1436.8

Step-by-step explanation:

Variables and symbols:

  • r = radius
  • V = volume
  • A = surface area
  • C = circumference
  • π = pi = 3.1415926535898
  • √ = square root

Volume of a sphere in terms of radius:

V = \frac{4}{3}\pi r^3 , V \approx 4.1888r^3

To calculate the volume of a sphere:

Usually the hardest part is measuring or estimating the diameter of the sphere. Special tools exist for smaller parts like balls in ball-bearings, but it gets more complicated if the size is large. Knowing that the diameter is the largest internal measurement you can take should help.

Once you have the measurement, to find the volume use the formula above, in which π is the well-known mathematical constant equal to about 3.14159. To adjust for a half-sphere calculation, just divide the result by two.

Spheres and half-spheres are useful in engineering and architecture due to their property of being able to take equal amounts of pressure or force from each direction.

Solution:

V=\frac{4}{3} \pi r^{3} =\frac{4}{3} *\pi *7^{3}  \approx1436.75504

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5 0
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Answer:

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2 years ago
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