Answer:
yes another flavor should be in the bag. because the problem stated that there are three different flavor, and only two flavors were mentioned in the problem. the probability of getting the third flavor is 5/7 i guess, because it think the probability of the second flavor was the answer when you added both the numerator and the denominator of 1/3 by 2. like 1/3+2=3/5, so if you added 2 to both the numerator and the denominator of 3/5, you will get 5/7. but i am not so sure about this, i'm sorry in advance.
Answer:
5,000
Step-by-step explanation:
Answer:
all real numbers such as 0<y<40
Step-by-step explanation:
as the tub is draining water, it will never exceed original amount of 40. the lowest amount of water you can have is 0, never below 0
Let’s call the number of gallons of 30% solution “x”. If we mix together 40 gallons and x gallons of solution, we’re going to come out with a total of 40 + x gallons of that 20% solution. Mathematically, this is
40(12%) + x(30%) = (40 + x)(20%)
With the percents as decimals:
40(0.12) + x(0.3) = (40 + x)(0.2)
Simplifying, we have:
4.8 + 0.3x = 8 + 0.2x
Collecting the x terms on one side and the constants on the other:
0.1x = 3.2
And multiplying both sides by 10 to find x:
x = 32
So, you’ll need 32 gallons of 30% solution to yield 40 + 32 = 72 gallons of 20% solution.
<em>Answer:</em>
<h3>
<em>B'=</em><em>(</em><em>1</em><em>6</em><em>,</em><em>1</em><em>4</em><em>)</em></h3>
<em>It </em><em>is </em><em>clear </em><em>from </em><em>the </em><em>co-ordinates</em><em> </em><em>of </em><em>the </em><em>square </em><em>that </em><em>CD </em><em>is </em><em>parallel </em><em>to </em><em>X </em><em>axis </em><em>and </em><em>BC </em><em>is </em><em>parallel </em><em>to </em><em>y-axis.</em><em> </em><em>So,</em><em>X=</em><em>8</em><em>,</em><em>y=</em><em>7</em>
<em>so </em><em>the </em><em>co-ordinates</em><em> </em><em>of </em><em>B=</em><em>(</em><em>8</em><em>,</em><em>7</em><em>)</em>
<em>Now </em><em>after </em><em>dilation</em><em> </em><em>of </em><em>factor </em><em>2</em><em>,</em><em> </em><em>all </em><em>coordinates</em><em> </em><em>will </em><em>be </em><em>multiplied</em><em> </em><em>by</em><em> </em><em>2</em><em>.</em>
<em>So </em><em>B'=</em><em>(</em><em>1</em><em>6</em><em>,</em><em>1</em><em>4</em><em>)</em>
<em>hope </em><em>it</em><em> helps</em>