1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
umka21 [38]
3 years ago
10

What's the next three numbers in this inductive reasoning pattern 10,7,4,1

Mathematics
1 answer:
pentagon [3]3 years ago
3 0
10, 7, 4, 1, -2, -5, -8
You might be interested in
Find the surface area of the pyramid. the surface area of the pyramid is __in squared.
iVinArrow [24]

Answer:

561.08in^{2}

Step-by-step explanation:

S A = lw + l \sqrt{(\frac{w}{2})^{2}  + h^{2}  } + w \sqrt{(\frac{l}{2})^{2} + h^{2}  }

SA = 14(14) + 14 \sqrt{(\frac{14}{2})^{2} + 11^{2}  }+ 14 \sqrt{(\frac{14}{2})^{2} + 11^{2}  } = 561.08in^{2}

4 0
1 year ago
Please help me with this problem
Alexus [3.1K]
(a) It is leaking 18 liters per minute.

Explanation : From 15 minutes to 20 minutes, your starting point at 15 is 590 liters and at 20 you have exactly 500. Next you have 25 which is now at 410. So it's leaking 90 liters every five minutes, so of course dividing the two (90 ÷ 5) you get 18.

(a)² it increases for about the same time that it would decrease of course.

(b) The vat started at 860 liters before they started draining it.

Explanation : Well, all it takes is just working backwards, add 90 liters to the liters at 15 minutes and deduct five minutes from 15. Do this process until you arrive at 0. It's simple
7 0
3 years ago
What is and equation line that passes through the point (8,-5) and is parallel to the line 5x+4y=24
GenaCL600 [577]

Answer:

5x + 4x = 20

Step-by-step explanation:

You have your x and y values and if you substitute them in you find yourself with 40 - 20 = 24 this doesn't make sense. So you get another answer which can be set to 20 and 40 - 20 = 20 therefore you you can make sure that your line intersects with your x and y values.

4 0
3 years ago
What is the best next step in the construction of the perpendicular bisector of
Musya8 [376]

C, not sure but C. It makes sense to me & I got it right when I did it

4 0
3 years ago
Read 2 more answers
Suppose you want to know how fast you traveled from the park to the library. As you moved, your speed varied from second to seco
frutty [35]

Step-by-step explanation:

In order to describe speed of an object, we must describe the average speed of the entire trip. It is equal to the distance moved divided by time taken.

If a person covers a distance of 1 km to the library in 15 minutes, we can find its average speed.

Firstly, we convert 15 minutes to hour, 15 min = 0.25 hours

Now, using formula of speed = distance/time

v=\dfrac{1\ km}{0.25\ h}\\\\v=4\ km/h

It means that the average speed of the person is 4 km/h. Hence, the given statement is true.

6 0
2 years ago
Other questions:
  • On average, for every 15 points scored by his basketball team, Riley scores 4 of them. About how many points would you expect Ri
    10·1 answer
  • Please help, 10 points
    12·1 answer
  • There are 80 red balloons and 20 green balloons each package of balloons. What is the unit rate in red balloons per green balloo
    11·2 answers
  • Note: Enter your answer and show all the steps that you use to solve this problem in the space provided,
    5·1 answer
  • Shawn bought fruit last week, consisting of 2.26 pounds of bananas, ​ 1.5 pounds of grapes, and a watermelon that weighed 6.78 p
    5·2 answers
  • On a coordinate plane, a line goes through points (negative 3, negative 3) and (0, 3).
    6·1 answer
  • Owen's goal is to drink 6060 ounces of water each day for three days. On the first day, he met \frac{2}{3} 3 2 ​ of his daily go
    12·1 answer
  • Trigonometri odevlerin islemi
    14·2 answers
  • How many solutions exist for the system of equations in the graph?
    6·1 answer
  • .753 repeating as a fraction
    10·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!