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seraphim [82]
3 years ago
7

What is the next term in this geometric sequence? 104, -52, 26, -13, ...

Mathematics
1 answer:
Yanka [14]3 years ago
8 0

Answer:

The Answer is 6.5 because you are dividing by negative 2

Step-by-step explanation:

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Firlakuza [10]
The correct answer is c=5. hope this helps.
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What is t cubed times 4
Marina CMI [18]

Answer:

t^​3*​4

Step-by-step explanation:

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Please answer this question​
Tems11 [23]

\bold{\huge{\underline{ Solution }}}

<h3><u>Given </u><u>:</u><u>-</u><u> </u></h3>

• \sf{ Polynomial :- ax^{2} + bx + c }

• The zeroes of the given polynomial are α and β .

<h3><u>Let's </u><u>Begin </u><u>:</u><u>-</u><u> </u></h3>

Here, we have polynomial

\sf{ = ax^{2} + bx + c }

<u>We </u><u>know </u><u>that</u><u>, </u>

Sum of the zeroes of the quadratic polynomial

\sf{ {\alpha} + {\beta} = {\dfrac{-b}{a}}}

<u>And </u>

Product of zeroes

\sf{ {\alpha}{\beta} = {\dfrac{c}{a}}}

<u>Now, we have to find the polynomials having zeroes </u><u>:</u><u>-</u>

\sf{ {\dfrac{{\alpha} + 1 }{{\beta}}} ,{\dfrac{{\beta} + 1 }{{\alpha}}}}

<u>T</u><u>h</u><u>erefore </u><u>,</u>

Sum of the zeroes

\sf{ ( {\alpha} + {\dfrac{1 }{{\beta}}} )+( {\beta}+{\dfrac{1 }{{\alpha}}})}

\sf{ ( {\alpha} + {\beta}) + ( {\dfrac{1}{{\beta}}} +{\dfrac{1 }{{\alpha}}})}

\sf{( {\dfrac{ -b}{a}} ) + {\dfrac{{\alpha}+{\beta}}{{\alpha}{\beta}}}}

\sf{( {\dfrac{ -b}{a}} ) + {\dfrac{-b/a}{c/a}}}

\sf{ {\dfrac{ -b}{a}} + {\dfrac{-b}{c}}}

\bold{{\dfrac{ -bc - ab}{ac}}}

Thus, The sum of the zeroes of the quadratic polynomial are -bc - ab/ac

<h3><u>Now</u><u>, </u></h3>

Product of zeroes

\sf{ ( {\alpha} + {\dfrac{1 }{{\beta}}} ){\times}( {\beta}+{\dfrac{1 }{{\alpha}}})}

\sf{ {\alpha}{\beta} + 1 + 1 + {\dfrac{1}{{\alpha}{\beta}}}}

\sf{ {\alpha}{\beta} + 2 + {\dfrac{1}{{\alpha}{\beta}}}}

\bold{ {\dfrac{c}{a}} + 2 + {\dfrac{ a}{c}}}

Hence, The product of the zeroes are c/a + a/c + 2 .

<u>We </u><u>know </u><u>that</u><u>, </u>

<u>For </u><u>any </u><u>quadratic </u><u>equation</u>

\sf{ x^{2} + ( sum\: of \:zeroes )x + product\:of\: zeroes }

\bold{ x^{2} + ( {\dfrac{ -bc - ab}{ac}} )x + {\dfrac{c}{a}} + 2 + {\dfrac{ a}{c}}}

Hence, The polynomial is x² + (-bc-ab/c)x + c/a + a/c + 2 .

<h3><u>Some </u><u>basic </u><u>information </u><u>:</u><u>-</u></h3>

• Polynomial is algebraic expression which contains coffiecients are variables.

• There are different types of polynomial like linear polynomial , quadratic polynomial , cubic polynomial etc.

• Quadratic polynomials are those polynomials which having highest power of degree as 2 .

• The general form of quadratic equation is ax² + bx + c.

• The quadratic equation can be solved by factorization method, quadratic formula or completing square method.

6 0
2 years ago
Please help me idk this
marusya05 [52]

Answer:

56.52

Step-by-step explanation:

you do 3.14 times 18

8 0
4 years ago
The first term in an arithmetic sequence is 5. The fourth term in the sequence is −4. The tenth term
d1i1m1o1n [39]

Answer:

<h2>          aₙ = -3n + 8</h2>

Step-by-step explanation:

The nth term of an arithmetic sequence:  aₙ = a₁ + d(n - 1)

{d = common difference}

a₁ = 5

a₄ = 5 + d(4 - 1)

-4 = 5 + 3d

-4 - 5 = 3d

3d = -9

 d = -3

Therefore;

                  aₙ = 5 + (-3)(n - 1)

                   aₙ = -3n + 8

Check:  a₁₀ = 5 + (-3)(10 - 1) = 5 - 27 = - 22

3 0
3 years ago
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