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Nadusha1986 [10]

2 years ago

10

A savings account accrues interest at a rate of 3.0% yearly. If someone opens an account with $2,500, how much money would the a

ccount have after 4 years?

1 answer:

stira [4]2 years ago

6 0

<span>2500(1.03)^5 that's the equation .
which means it would be 2,898.18</span>

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Write an equation for an ellipse centered at the origin, which has foci at (0,\pm\sqrt{63})(0,± 63 )left parenthesis, 0, comma

steposvetlana [31]

Answer:

$\frac{x^{2} }{4312 } + \frac{y^{2} }{8281 }$

Step-by-step explanation:

Since the foci are at(0,±c) = (0,±63) and vertices (0,±a) = (0,±91), the major axis is the y- axis. So, we have the equation in the form (with center at the origin) $\frac{x^{2} }{b^{2} } + \frac{y^{2} }{a^{2} }$ .

We find the co-vertices b from b = ±√(a² - c²) where a = 91 and c = 63

b = ±√(a² - c²)

= ±√(91² - 63²)

= ±√(8281 - 3969)

= ±√4312

= ±14√22

So the equation is

$\frac{x^{2} }{(14\sqrt{22}) ^{2} } + \frac{y^{2} }{91^{2} } = \frac{x^{2} }{4312 } + \frac{y^{2} }{8281 }$

8 0

3 years ago

An electrician sent Bonnie an invoice in the amount of 'a' dollars for 6 hours of work that was done on Saturday. The electricia

Mazyrski [523]

Answer:

(a-f)/6 = r

Step-by-step explanation:

The total Bonnie must pay is the weekend fee plus the hourly rate times the hours worked

Cost = weekend fee * hourly rate* hours

hours = 6

weekend fee =f

hourly rate = r

Cost = a dollars

Substituting in what we know

a = f+ 6r

We want to solve for r

Subtract f from each side

a-f =f-f +6r

a-f = 6r

Divide each side by 6

(a-f)/6 = 6r/6

(a-f)/6 = r

4 0

3 years ago

Help please! Will pick the Brainliest.<br> (sorry if it’s sideways)

KatRina [158]

1.

$(x^2y^8)^\frac{2}{3}=x^{2\cdot\frac{2}{3}}y^{8\cdot\frac{2}{3}}=x^{\frac{4}{3}}y^{\frac{16}{3}}=x^{1\frac{1}{3}}y^{5\frac{1}{3}}=x^1x^\frac{1}{3}y^5y^\frac{1}{3}=xy^5\sqrt[3]{x}\sqrt[3]{y}=\boxed{xy^5\sqrt[3]{xy}}$

Answer B)

2.

$\frac{1}{3}\left(\frac{2}{15}x-\frac{2}{3}\right)>x+\frac{1}{5}\quad|\cdot3\\\\\\\frac{2}{15}x-\frac{2}{3}>3x+\frac{3}{5}\quad|\cdot15\\\\\\2x-\frac{30}{3}>45x+\frac{45}{5}\\\\2x-10>45x+9\\\\-10-9>45x-2x\\\\-19>43x\quad|:43\\\\\boxed{x$

Answer B)

3.

$\sqrt{14xy}\cdot\sqrt{12}\cdot\sqrt{30y}=\sqrt{14\cdot12\cdot30}\cdot\sqrt{xy^2}=\sqrt{2\cdot7\cdot3\cdot4\cdot2\cdot3\cdot5}\cdot\sqrt{xy^2}=\\\\=\sqrt{2^2\cdot3^2\cdot2^2\cdot5\cdot7}\cdot\sqrt{xy^2}=2\cdot3\cdot2\cdot\sqrt{35}\cdot y\cdot\sqrt{x}=\boxed{12y\sqrt{35x}}$

3 0

3 years ago

PLEASE HELP!<br> find the missing value:

Bess [88]

Answer:

um

Step-by-step explanation:

3 0

3 years ago

Please send me answer. tomorrow is my exam.

masha68 [24]

Answer:

The table is attached below and ogive also.

Step-by-step explanation:

Given

The following distribution is given below

First we find the cumulative frequency.

And then we convert it into a less than type ogive.

find the cumulative frequency shown below clearly

And convert it into less than type of cumulative frequency distribution is also done in next table, the daily income is less than daily income upper limit.

In this graph x-axis is daily income and y-axis is number of workers

6 0

2 years ago