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Vanyuwa [196]
3 years ago
14

What is 1-0 i will give brainliest

Mathematics
2 answers:
dmitriy555 [2]3 years ago
7 0
Answer: It’s 1


Explanation: it’s 1
rosijanka [135]3 years ago
5 0
It’s 0 it’s 0 hehe bye bye
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The local meteorologist is converting temperatures from Celsius to Fahrenheit. she knows that the formula for the conversion fro
andreev551 [17]
In this equation, we are solving for f. The first thing we have to do is get rid of the denominator, so we have to multiply both sides by 9, which leaves us with 9C=5*(f-32). Then we divide both sides by 5, which is 9/5C=f-32. The last thing we have to do is add 32 to both sides to isolate f, which gives us our final equation of (5/9)C+32=f. 
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Seven cakes cost £2.10 how much do 10 cakes cost
Len [333]
Ten cakes costs $2.19 (pounds, but I don't have a pounds symbol on my computer) because if you divide $2.10 by seven you get $0.3, and if you add 3×0.3 (because we have seven, and we need to add three more to get ten) we get $0.9.
 
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3 years ago
Evaluate the expression for the given variable <br>-4p+1 when p=2​
Rama09 [41]
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8 0
2 years ago
What is the solution to the equation?
ki77a [65]

Answer:

7

Step-by-step explanation:

3 {(x + 9)}^{ \frac{3}{4} }  = 24 \\  \\ {(x + 9)}^{ \frac{3}{4} }  =  \frac{24}{3}  \\  \\  {(x + 9)}^{ \frac{3}{4} }  =  8  \\  \\  {(x + 9)}^{ \frac{3}{4} }  =   {2}^{3}   \\  \\ (x + 9) =  {2}^{3 \times  \frac{4}{3} }  \\  \\ x + 9 =  {2}^{4}  \\  \\ x + 9 = 16 \\  \\ x = 16 - 9 \\  \\ x = 7

7 0
3 years ago
I need help from uh all..​
DanielleElmas [232]

Answer:

Step-by-step explanation:

Given expression is,

\text{cot}A=\frac{1}{2}(\text{cot}\frac{A}{2}-\text{tan}\frac{A}{2})

To prove this identity we will take the right side of the identity,

\frac{1}{2}(\text{cot}\frac{A}{2}-\text{tan}\frac{A}{2})=\frac{1}{2}(\frac{1}{\text{tan}\frac{A}{2}}-tan\frac{A}{2})

                         =\frac{1}{2}(\frac{1-\text{tan}^2\frac{A}{2}}{tan\frac{A}{2}})

                         =\frac{1}{2}[\frac{2(1-\text{tan}^2\frac{A}{2})}{2tan\frac{A}{2}}]

                         =\frac{1}{2}(\frac{2}{\text{tan}A} ) [Since \text{tan}A=\frac{2\text{tan}\frac{A}{2}}{1-\text{tan}^2\frac{A}{2}}]

                         = cot A

Hence right side of the equation is equal to the left side of the equation.

3 0
3 years ago
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