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bogdanovich [222]
3 years ago
11

This list is in _____ order.

Computers and Technology
2 answers:
bixtya [17]3 years ago
8 0

The correct answer is C. Descending

Explanation:

In lists, the descending order implies the information is organized from the last to the first, in the case of numbers this occurs as the largest number is placed first and the smallest is last. Additionally, in the case of words, the descending order means to organize words from Z to A. This order differs from the ascending and alphabetical order that organizes words from A to Z. In the case presented, the descending order is used because the first element (Zah Smith) begins by Z which is the last letter in the alphabet, this is followed by Mason Fitzpatrick and finally by Billings considering M is before A in the descending order.

Illusion [34]3 years ago
5 0
Descending.

Alphabetical order is from A-Z.
Ascending order is from A-Z.
Descending order is from Z-A.

Hope this helps!
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EastWind [94]

Adam might have forgotten to loop the guessing code, meaning that instead of letting him guess multiple times, it simply does it once and ends the program. This could be fixed by adding a while loop, or something of the sort, that doesn't let the user finish the program until they guess the number correctly, while adding to the variable that stores the number of guesses each loop.

5 0
3 years ago
2. Use inheritance to create a hierarchy of Exception classes -- EndOfSentenceException, PunctuationException, and CommaExceptio
Lelechka [254]

Answer:

See explaination

Explanation:

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//Create a class EndOfSentenceException that

//extends the Exception class.

class EndOfSentenceException extends Exception

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{

System.out.println(str);

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}

CommaException.java

//Create a class CommaException that extends the class

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class CommaException extends EndOfSentenceException

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//Define the constructor of CommaException.

public CommaException(String str)

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class PunctuationException extends EndOfSentenceException

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&& !(str.endsWith("?")))

{

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throw new PunctuationException("The sentence "

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5 0
2 years ago
suppose a malloc implementation returns 8-byte aligned addresses and uses an explicit free list where the next and previous poin
Naya [18.7K]

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4004 because malloc internally always allocates at least four bytes. Your program would be 4000 if you added four bytes, making it 4004. may crash only when you access byte n+1. Additionally, the operating system typically only protects pages of memory.

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To learn more about internal management here

brainly.com/question/13398903

#SPJ1

Full Question = Suppose a malloc implementation returns 8-byte aligned addresses and uses an explicit free list where the next and previous pointers are each 32-bits. Blocks have a 32-bit header and 32-bit footer, where the low-order bit of the header and footer are used to indicate whether the block is allocated (1) or free (0). Furthermore, the block size (which includes the header, payload, footer, and any necessary padding) is rounded up to the nearest multiple of 8, and this size (in bytes) is stored in the header and footer. Assume any padding must be between the payload and the footer.

a) If we call malloc(1), what block size will be allocated, in bytes?

b) With the same conditions, and assuming we've already called malloc(1), if the heap used by malloc starts at address 0x4000 (16384 in decimal), what address would be returned if we then called malloc(32)?

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1 year ago
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Zigmanuir [339]

Answer:

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7 0
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umka21 [38]
64 bit the likely hood of it failing is much less
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