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spin [16.1K]
3 years ago
5

Suppose two hosts, A and B, are separated by 20,000 kilometers and are connected by a direct link of R = 2 Mbps. Suppose the pro

pagation speed over the link is 2.5 108 meters/sec.
a. Calculate the bandwidth-delay product, R dprop.
b. Consider sending a file of 800,000 bits from Host A to Host B. Suppose the file is sent continuously as one large message. What is the maximum number of bits that will be in the link at any given time?
Computers and Technology
1 answer:
AnnZ [28]3 years ago
3 0

Answer:

a. (210^6)((210^7)/(2.510^8)) = 1.610^5 bits or 160,000 bits

b. 1.6*10^5 bits or 160,000 bits

c. Bandwidth delay product of link is maximum number of bits that can be in the link

d. Width of bit = Length of link / bandwidth-delay product so 1 bit is 125 meters long. Yes, this is longer than a football field.

e. Width of bit = s/R

Hope this helps :)

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