Question

Suppose two hosts, A and B, are separated by 20,000 kilometers and are connected by a direct link of R = 2 Mbps. Suppose the propagation speed over the link is 2.5 108 meters/sec.
a. Calculate the bandwidth-delay product, R dprop.
b. Consider sending a file of 800,000 bits from Host A to Host B. Suppose the file is sent continuously as one large message. What is the maximum number of bits that will be in the link at any given time?

Answer 1

Answer:

a. (210^6)((210^7)/(2.510^8)) = 1.610^5 bits or 160,000 bits

b. 1.6*10^5 bits or 160,000 bits

c. Bandwidth delay product of link is maximum number of bits that can be in the link

d. Width of bit = Length of link / bandwidth-delay product so 1 bit is 125 meters long. Yes, this is longer than a football field.

e. Width of bit = s/R

Hope this helps :)