Answer:
<h2>A. <em><u>2</u></em><em><u>1</u></em><em><u>4</u></em><em><u>,</u></em><em><u>0</u></em><em><u>0</u></em><em><u>0</u></em></h2>
Step-by-step explanation:
<h3>#CarryOnLearning</h3>
Answer:
-1.375
Step-by-step explanation:
Answer:
a. Total field goal points scored in the first two quarters, in simplest linear expression form is: 3x - 4.
b. The total points scored in the game, in simplest linear expression form is: 6x - 1.
a. The goal points scored in the first two quarters are expressed in linear forms as: 2x - 6 and x + 2.
The total field goal points in the first two quarters = 2x - 6 + x + 2
Add like terms
3x - 4
b. The total points scored in the game = 2x - 6 + x + 2 + 2x + x - 6 + 9
Add like terms and simplify the expression
2x - 6 + x + 2 + 2x + x - 6 + 9
6x - 1
Step-by-step explanation:
A^2 + b^2 = c^2
9^2 + b^2 = 15^2
81 + b^2 = 225
225 - 81 = b^2
144 = b^2
square root of 144 = 12
b = 12
Given the parameters in the diagrams, we have;
4. ∆ABC ≈ ∆DEF by ASA
5. UW ≈ XZ by CPCTC
6. QR ≈ TR by CPCTC
<h3>How can the relationship between the triangles be proven?</h3>
4. The given parameters are;
<B = <E = 90°
AB = DE Definition of congruency
<A = <D Definition of congruency
Therefore;
- ∆ABC ≈ ∆DEF by Angle-Side-Angle, ASA, congruency postulate
5. Given;
XY is perpendicular to WZ
UV is perpendicular to WZ
VW = YZ
<Z = <W
Therefore;
∆UVW ≈ ∆XYZ by Angle-Side-Angle, ASA, congruency postulate
Which gives;
- UW is congruent to XZ, UW ≈ XZ, by Corresponding Parts of Congruent Triangles are Congruent, CPCTC
6. Given;
PQ is perpendicular to QT
ST is perpendicular to QT
PQ ≈ ST
From the diagram, we have;
<SRR ≈ <PRQ by vertical angles theorem;
Therefore;
∆QRP ≈ ∆TRS by Side-Angle-Angle, SAA, congruency postulate
Which gives;
- QR ≈ TR by Corresponding Parts of Congruent Triangles are Congruent, CPCTC
Learn more about congruency postulates here:
brainly.com/question/26080113
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