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Gemiola [76]
3 years ago
9

Let mu denote the true average number of minutes of a television commercial. Suppose the hypothesis H0: mu = 2.1 versus Ha: mu &

gt; 2.1 are tested. Assuming the commercial time is normally distributed, give the appropriate rejection region when there is a random sample of size 20 from the population and we would like to test at the level of significance 0.01. Let T be the appropriate test statistic.
A, T > 2.539
B. > 2.845
C. T> .528D. T >2.861

Mathematics
1 answer:
natka813 [3]3 years ago
7 0

Answer:

A. T > 2.539

Step-by-step explanation:

We have a hypothesis test of the mean, with unknown population standard deviation.

The hypothesis are:

H_0: \mu = 2.1 \\\\H_a: \mu > 2.1

From the hypothesis we can see that the test is right-tailed, so the critical value of t should be a positive value.

The degrees of freedom can be calculated as:

df=n-1=20-1=19

The significance level is 0.01, so the critical value tc should be the one that satisfies:

P(t>t_c)=0.01

Looking up in a t-table, for 19 degrees of freedom, this critical value is tc=2.539.

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