RSQ = 32
TSQ = 58
X = 5
Hope this helps!!!!
Answer:
To find the inverse, interchange the variables and solve for y
f^−1(x)=−7x+7
Hope I helped :)
Answer:
{x = -3
, y=2 (Isolved for both variables be elimination)
Step-by-step explanation:
Solve the following system:
{3 x + 5 y = 1 | (equation 1)
7 x + 4 y = -13 | (equation 2)
Swap equation 1 with equation 2:
{7 x + 4 y = -13 | (equation 1)
3 x + 5 y = 1 | (equation 2)
Subtract 3/7 × (equation 1) from equation 2:
{7 x + 4 y = -13 | (equation 1)
0 x+(23 y)/7 = 46/7 | (equation 2)
Multiply equation 2 by 7/23:
{7 x + 4 y = -13 | (equation 1)
0 x+y = 2 | (equation 2)
Subtract 4 × (equation 2) from equation 1:
{7 x+0 y = -21 | (equation 1)
0 x+y = 2 | (equation 2)
Divide equation 1 by 7:
{x+0 y = -3 | (equation 1)
0 x+y = 2 | (equation 2)
Collect results:
Answer: {x = -3
, y=2
The app uses 2^28 bytes.
Step-by-step explanation:
- Step 1: Given total storage used by the app = 4^4 Megabytes. Also, 1 MB = 2^20 bytes. Find total storage used by app in bytes.
⇒ 4^4 × 2^20 = (2²)^4 × 2^20 = 2^8 × 2^20
= 2^8+20
= 2^28 bytes (using the law of exponents a^m × a^n = a^m+n)
Answer:
Integers: is the set of all the numbers that can be created by adding ones or subtracting ones a given number of times to zero.
for example:
4 = 0 + 1 + 1+ 1 +1 is an integer.
-3 = 0 - 1 - 1- 1 is an integer.
0 is also an integer, you add ones zero times.
Then 5 examples of integers can be:
-10, -5, 0, 4, 18
Whole numbers: this set is the set of the positive integers and the zero.
Then 5 examples are:
0, 1, 4, 6, 173
Rational: All the numbers that can be written as a quotient of two integers.
5 examples are:
2/2, 7/3, 4/16, 100/10, -500/1048
Natural: Is the set of the positive integers.
5 examples are:
1, 4, 6, 120, 47
Irrational: Are numbers that have infinite digits after the decimal point, such that there is no pattern in those digits. The squareroots of prime numbers are always irrational numbers.
5 examples are:
pi, √2, √3, √5, √13
where pi = 3.141592653...
Is the relation between the perimeter of a circle and its diameter.
perimeter = diameter*pi.
