Answer:
-23
Step-by-step explanation:
We are given the functions;
h(x) = 5x - 3 and j(x) = -2x
Now, we want to find h[j(2)]
j(2) = -2(2)
j(2) = -4
Thus;
h(-4) = 5(-4) - 3
h(-4) = -20 - 3
h(-4) = - 23
16.5 degrees below the starting temp, whatever that is. If its 0, then -16.5 degrees.
The first equation would be (.5)5-11=-8.5, because the metal has been cooling for 5 hours.
The device that 'aids' in the cooling would be -5-3=-8, because it is a separate variable that cools the metal, so the amount the device cools is independent of the natural cooling amount, and the equation is independent of the natural cooling equation.
You then add -8.5 and -8, because the device has lowered 8.5 degrees and 8 degrees. This equals -16.5 degrees, or a decrease of 16.5 degrees.
16.30 and 16.3 equal. If you ever have a problem like that then you just add on a zero.
Example:
19.4500 = 19.45 Just add two zeros on the end
19.45 + two zeros = 1.4500
Answer:
65°
Step-by-step explanation:
JM = JK (all sides of a rhombus are equal)
Angle JKM = 25° (isosceles triangle)
Angle JKL = 50° (consecutive angles of rhombus)
Angle MKL = 25° (angle subtraction)
Angle MLK = 130° (opposite angles of a rhombus)
Angle KLN = 50° (angles on a straight line)
Angle LKN = 40° (angle sum of triangle)
Angle MKN = 65° (angle addition)
