Based on the graph (see attachment), Tariq is 4 minutes after he left his house, until he got back home.
<h3>What is distance?</h3>
Distance can be defined as the amount of ground covered (traveled) by a physical object or body over a specific period of time, regardless of its direction, starting point or ending point.
<h3>What is a graph?</h3>
A graph can be defined as a type of chart that's commonly used to graphically represent data on both the horizontal and vertical lines of a cartesian coordinate, which are the x-axis and y-axis.
By critically observing the graph (see attachment) which models the time that elapses over the distance covered by Tariq, we have:
Time = 10 minutes - 6 minutes
Time = 4 minutes.
In conclusion, we can infer and logically deduce that Tariq is 4 minutes after he left his house, until he got back home.
Read more on graphs here: brainly.com/question/25875680
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Answer:
Step-by-step explanation:
Here you go mate
Step 1
-5-(-6) Equation/Question
Step 2
-5-(-6) Simplify
5-6
Step 3
5-6 Subtract them
Answer
1
Hope this helps
Let x represent the larger number.
1/(x -28) +4/x = 1/6
Multiplying by the product of denominators, we have
6x +24(x -28) = x(x -28)
In standard form, this is
x^2 -58x +672 = 0
(x -42)(x -16) = 0
The two numbers are (-12 and 16) or (14 and 42).
UV is a <u>perpendicular</u> <u>bisector</u> of RT. A perpendicular bisector UV is a line that does two things:
- cuts the line segment RT into two equal pieces or bisects it;
- makes a right angle with the line segment RT (is perpendicular).
Consider an arbitrary point X on the line RT that differs from S. Connect points U, V and X to form triangle UVX. Line XS will be the height and the median of the triangle UVX. This gives you that triangle UVX will be isosceles triangle with base UV.
Answer: correct choice is D
There would be infinite solutions if no initial-value problem is specified. For example, take the differential equation written below:
dy = 3dx
When you differentiate that, the equation would become:
y - y₀ = 3(x - x₀)
Now, there can be arbitrary values of x₀ and y₀. If no initial-value problem is specified, you cannot solve the problem because there are infinite solution. Example of an initial value problem is: when x₀ = 2, y₀ = 2. If we had that, we can find a solution to the differential equation.
