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Neporo4naja [7]
3 years ago
6

Explain the circumstances for which the interquartile range is the preferred measure of dispersion. What is an advantage that th

e standard deviation has over the interquartile​ range?
Mathematics
1 answer:
KatRina [158]3 years ago
8 0

Answer:

Explain the circumstances for which the interquartile range is the preferred measure of dispersion

Interquartile range is preferred when the distribution of data is highly skewed (right or left skewed) and when we have the presence of outliers. Because under these conditions the sample variance and deviation can be biased estimators for the dispersion.

What is an advantage that the standard deviation has over the interquartile​ range?

The most important advantage is that the sample variance and deviation takes in count all the observations in order to calculate the statistic.

Step-by-step explanation:

Previous concepts

The interquartile range is defined as the difference between the upper quartile and the first quartile and is a measure of dispersion for a dataset.

IQR= Q_3 -Q_1

The standard deviation is a measure of dispersion obatined from the sample variance and is given by:

s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

Solution to the problem

Explain the circumstances for which the interquartile range is the preferred measure of dispersion

Interquartile range is preferred when the distribution of data is highly skewed (right or left skewed) and when we have the presence of outliers. Because under these conditions the sample variance and deviation can be biased estimators for the dispersion.

What is an advantage that the standard deviation has over the interquartile​ range?

The most important advantage is that the sample variance and deviation takes in count all the observations in order to calculate the statistic.

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Pls someone help me
jarptica [38.1K]

Answer:

Upper left corner

Step-by-step explanation:

Divide the distance D over the time T. If you travel D = 325 miles for T = 5 hours, then your speed or rate R is

R = D/T = 325/5 = 65

So you're traveling at 65 miles an hour if you travel 325 miles in 5 hours, which is what the upper left corner diagram is showing.

4 0
3 years ago
Find the distance between points 5,9 and (7,-7) using the distance formual
mart [117]
========================================
Formula to find Distance:
========================================
\text{Distance = }  \sqrt{X2-X1)^2 + (Y2-Y1)^2}

========================================
Find Distance between (5, 9) and (7, -7):
========================================

X2 = 5, X1 = 7, Y2 = 9, Y1 = -7, therefore,

\text{Distance = }  \sqrt{(9+7)^2 + (5-7)^2}
\text{Distance = }  \sqrt{(16)^2 + (2)^2}
\text{Distance = }  \sqrt{256 + 4}
\text{Distance = }  \sqrt{260}
\text{Distance = } 16.12 \text{ units}

========================================
Answer: 16.12 units
========================================
5 0
3 years ago
At the car wash fundraiser jenna's team washed 14 cars in 45 minutes. if they keep up at that rate, how many cars can the team w
lys-0071 [83]
I think the answer would be about 25 but i´m not real sure.
3 0
3 years ago
What is the inverse of multiplying by 6 ?​
marusya05 [52]

Answer:

The multiplicative inverse of 6 is 1/6.

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Y-5=6(x-7)<br><br> A. (5,7)<br> B. (7,5)<br> C. (-7,-5)<br> D. (-5,-7)
lidiya [134]

Answer:

B

Step-by-step explanation:

7-7 x 5 = 0

5-5 = 0

8 0
4 years ago
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