What is the sum of the first 11 terms of the arithmetic series in which a1= -12 and d=5?
1 answer:
Hello : the terme general is : an = a1 +(n-1)d a11 = a1+(11-1)×5 a11 = -12+50 a11 = 38 <span>the sum of the first 11 terms is : S11 = (11/2)(a1+a11) </span>S11 = (11/2)(-12+38) S11 = 143
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