Here you have a system of 2 equations and 2 unknowns. An easy way to solve this type is to isolate one of the variables.
12a + 2b = 8
2b = 8 - 12a
b =
b = 4 - 6a
Now plug 4 - 6a into equation 1 to solve for a.
a + 5(4 - 6a) = 19
a + 20 - 30a = 19
-29a = -1
a = 1/29 (answer)
Now plug a into the equation for b
b= 4 - 6(1/29)
b= 110/29 (answer)
Answer:
7.5
Step-by-step explanation:
(x+6)^(1/2)-5=x+1
(x+6)^(1/2)=x+6
((x+6)^(1/2))^2=(x+6)^2
x+6=x^2+12x+36
0=x^2+11x+30
(-11+(11^2-4(1)(30))^(1/2))/2
(-11+((1)^(1/2))/2
(-11+1)/2=-5
(-11-1)/2=-6
((-6)+6)^1/2-5=(-6)+1
(0^(1/2))-5=-5
-6 is non-extraneous
((-5)+6)^1/2-5=(-5)+1
(1^1/2)-5=-4
1-5=-4
-4=-4
-5 is non-extraneous
Answer:
D. 70°
Step-by-step explanation:
Given:
m<DGB = 35°
m<CGF = 75°
Required:
m<AGE
SOLUTION:
m<EGD = m<CGF (vertical angles are congruent)
m<EGD = 75°
m<AGE + m<EGD + m<DGB = 180° (angles on a straight line)
m<AGE + 75° + 35° = 180° (substitution)
m<AGE + 110° = 180°
Subtract 110 from each side of the equation
m<AGE = 180° - 110°
m<AGE = 70°
I think the number of ways is 671?