Answer:
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Step-by-step explanation:
Answer:
A) p(male)=20/30=2/3
b) p(female) = 10/30=1/3
c) p(11th grade) = 12/30=2/5
d) p(12th grade) = 18/30 = 3/5
e) p( girl and in 11th grade) =4/30=2/15
F) p(12 th grade and female) = 6/30 = 1/5
g) p(male and in 12th grade) = 12/30 = 2/5
h) p(male and if we know the student is female) = 0 if we know the student is male then she can't be male again. these are mutuallyinclusive event and they can't occur at once.FOR more details and solutions,clarification and more explanation contact me via my g mail at [email protected] and I will keep in touch....please leave your comment in thisg mail which is my tutor g mail account please.
Add (11/2)^2 to both sides
x^2 + 11x + (11/2)^2 = 3 + (11/2)^2
x^2 + 11x + (11/2)^2 = 133/4
(x + 11/2)^2 = 133/4
x + 11/2 = sqrt of (133/4)
Solutions are
x = (sqrt of (133) - 11))/2
x = (-sqrt of (133) -11))/2
160,000. because all we do is round the thousand place up since its above 5
