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bogdanovich [222]
3 years ago
10

How many thousands can go into 90 hundreds

Mathematics
1 answer:
lesya692 [45]3 years ago
3 0
To find this, multiply 90 by 100 to get 9000. Then divide by 100 to get 9.

9 thousands can go into 90 hundreds.
Hope this helped!
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Use the pythagorean theorem to find the distance between the points (4,3) and (-4,-3)
maxonik [38]

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Length of horizontal line = 8 units

a^2 + b^2 = c^2

6^2 + 8^2 = 100

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The distance between the two points is 10 units.

7 0
3 years ago
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The sum of two numbers is 34. Half of the first number plus one third of the second number is 14. What are the two numbers?
likoan [24]
First number 16, second number 18
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(a) A mixed hockey team of 11 must have at least 5 boys and at least 5 girls. There are 7 boys and 8 girls available for selecti
guajiro [1.7K]

Answer:

A) I) 49 teams

II)63 teams

B) 28 teams

Step-by-step explanation:

A) a team of 5 boys and 6 Girls

=7C5+ 8C6

= 21+28

= 49 teams

a team of 6 boys and 5 girls

= 7C6 + 8C5

= 7+56

= 63 teams

B) one girl is kept constant already and a guy has injury

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5 0
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The team won 10 of its 30 games and lost the rest. What was the team's win-loss ratio?
hammer [34]

Answer:

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Step-by-step explanation:

8 0
3 years ago
What are the first five terms, a1, a2, a3, a4, a5 of the sequence defined by an= n^2-9/ n^3 and how can the sequence be describe
Valentin [98]

The first five terms of the sequence are -8, -5/8, 0, 5/64 and 16/125

<h3>Recursive form of a sequence</h3>

Given the nth term of a sequence expressed as:

an= n^2-9/ n^3

Determine the first five terms

If n = 1

a1 = 1^2-9/ 1^3

a1 = -8/1

a1 = -8

If n = 2

a2 = 2^2-9/ 2^3

a2 = -5/8

If n = 3

a3= 3^2-9/ 1^3

a3 = 9-9/3^3

a3 = 0

If n = 4

a4 = 4^2-9/ 4^3

a4= 16-9/64

a4 = 5/64

If n = 5

a5 = 5^2-9/ 1^3

a5 = 25-9/5^3

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Hence the first five terms of the sequence are -8, -5/8, 0, 5/64 and 16/125

Learn more on recursive function here: brainly.com/question/489759

#SPJ1

6 0
2 years ago
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