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bogdanovich [222]
3 years ago
10

How many thousands can go into 90 hundreds

Mathematics
1 answer:
lesya692 [45]3 years ago
3 0
To find this, multiply 90 by 100 to get 9000. Then divide by 100 to get 9.

9 thousands can go into 90 hundreds.
Hope this helped!
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HELP PLZZZZZ
Dmitry_Shevchenko [17]

Answer: Option (D) Add the exponents and keep the same base. Then find the reciprocal and change the sign of the exponent.

Explanation:

Given expression:

(2^3)(2^{-4})

<em>Step-1: </em>Add the exponents and keep the same base by using x^a*x^b = x^{a+b} property.

(2^3)(2^{-4}) = 2^{(3+(-4))} = 2^{-1}

Step-2: The reciprocal of 2^{-1} is \frac{1}{2^{-1}}, which is 2^1

Step-3: The exponent of 2^1 is +1; therefore, change the sign of exponent. The end expression will now become:

2^{-1}

Hence, the correct option is (D) Add the exponents and keep the same base. Then find the reciprocal and change the sign of the exponent.

3 0
3 years ago
Read 2 more answers
A city park has 4 splash pads. Each splash pad is in the shape of a parallelogram with a base of 5.4 meters and a height of 3.8
r-ruslan [8.4K]
c) 82.08 m^2

Hope I helped! ( Smiles )
5 0
3 years ago
Dale has $1,000 to invest. He has a goal to have $2,400 in this investment in 12 years. At what annual rate compounded continuou
Hatshy [7]

Answer:

9%

Step-by-step explanation:

Given that

The invested amount is $1,000

The future value is $2,400

The time period is 12 years

We need to find out the annual rate that compounded continously

So,

As we know that

Amount = Present value × e^(rate × time)

$2,500 = $1,000 × e^(rate × 12)

2.5 = e^(rate × 12)

ln 2.5 = 10r

ln 2.5 ÷ 10 = r

r = 9%

3 0
2 years ago
Simplify the following expression. cot^2x secx-cosx
Solnce55 [7]

ANSWER

\cos(x)   \cot ^{2} (x)

EXPLANATION

The given expression is;

\cot^{2} (x)  \sec(x)  -  \cos(x)

Change everything to

\sin(x)

and

\cos(x)

This implies that,

\frac{ \cos^{2} (x) }{ \sin^{2} (x) }  \times ( \frac{1}{ \cos(x) } )-  \cos(x)

Cancel the common factors,

\frac{ \cos(x) }{ \sin^{2} (x) }  \times ( \frac{1}{1} )-  \cos(x)

\frac{ \cos(x) }{ \sin^{2} (x) }-  \cos(x)

\frac{ \cos(x)  -  \sin ^{2} (x)  \cos(x) }{ \sin^{2} (x) }

= \frac{ \cos(x)(1  -  \sin ^{2} (x) ) }{ \sin^{2} (x) }

= \frac{ \cos(x)(\cos^{2} (x) ) }{ \sin^{2} (x) }

= \cos(x)  \cot^{2} (x)

6 0
3 years ago
Find the value of x<br>Thanks!
statuscvo [17]
Hi there!

From the given information, we can infer that the inner quadrilateral has equal side lengths of x and 2x-3.

We can turn this into a mathematical equation with 1 variable.

x = 2x - 3

Subtract both sides by 2x

-x = -3

Multiply both sides by -1

x = 3

Have an awesome day! :)

~collinjun0827, Junior Moderator
7 0
3 years ago
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