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lidiya [134]
2 years ago
9

How many edgès does the figure have?

Mathematics
1 answer:
lbvjy [14]2 years ago
4 0

Depending on the shape

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If you can please help thank you
zysi [14]

Answer:

d) 2x^2 + 2x -59

Step-by-step explanation:

(x-8)(x+4) + (x-3)(x+9) *multiply each term (...)(...)*

x^2 - 4x - 32 + x^2 + 6x -27 *combine like terms*

2x^2 +2x - 59

7 0
3 years ago
PLEASE HELP ON TIMER!!!!!
Lesechka [4]

Answer:

8

Step-by-step explanation:

6 0
3 years ago
If a car travels 48 miles per hour, ABOUT how many miles does it travel in 5 hours?<br><br> Thanks!!
zimovet [89]
240, just multiply 48 by 5
5 0
2 years ago
Read 2 more answers
Amanda simplifies the following expression and shows her work below. What mistake did Amanda make that resulted in an incorrect
den301095 [7]

Answer:

A, She added before multiplying.

Step-by-step explanation:

First, start off by using GEMDAS.

Grouping

Exponents

Multiply

Divide

Add

Subtract

You work from left to right - so you obviously divide first, which Amanda did successfully. Then, you multiply, which is exactly where Amanda went wrong. She was supposed to multiply before adding the 3 with 4.

Not sure if this made sense,

8 0
2 years ago
In a right triangle ABC, CD is an altitude, such that AD=BC. Find AC, if AB=3 cm, and CD= 2 cm.
konstantin123 [22]

Consider right triangle ΔABC with legs AC and BC and hypotenuse AB. Draw the altitude CD.

1. Theorem: The length of each leg of a right triangle is the geometric mean of the length of the hypotenuse and the length of the segment of the hypotenuse adjacent to that leg.

According to this theorem,

BC^2=BD\cdot AB.

Let BC=x cm, then AD=BC=x cm and BD=AB-AD=3-x cm. Then

x^2=(3-x)\cdot 3,\\ \\x^2=9-3x,\\ \\x^2+3x-9=0,\\ \\D=3^2-4\cdot (-9)=9+36=45,\\ \\\sqrt{D}=\sqrt{45}=3\sqrt{5},\\ \\x_1=\dfrac{-3-3\sqrt{5} }{2}0.

Take positive value x. You get

AD=BC=\dfrac{-3+3\sqrt{5} }{2}\ cm.

2. According to the previous theorem,

AC^2=AD\cdot AB.

Then

AC^2=\dfrac{-3+3\sqrt{5} }{2}\cdot 3=\dfrac{-9+9\sqrt{5} }{2},\\ \\AC=\sqrt{\dfrac{-9+9\sqrt{5} }{2}}\ cm.

Answer: AC=\sqrt{\dfrac{-9+9\sqrt{5} }{2}}\ cm.

This solution doesn't need CD=2 cm. Note that if AB=3cm and CD=2cm, then

CD^2=AD\cdot DB,\\ \\2^2=AD\cdot (3-AD),\\ \\AD^2-3AD+4=0,\\ \\D

This means that you cannot find solutions of this equation. Then CD≠2 cm.

8 0
3 years ago
Read 2 more answers
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