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andreev551 [17]
3 years ago
10

What is the average of 69 and 50?PLEASE HELP​

Mathematics
1 answer:
hjlf3 years ago
7 0
(69+50)/2
(119)/2
59.5
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Students planted 4(2x+3y) amount of trees on saturday and then 3(5x+4) amount of trees on Sunday. What is the total amount of tr
algol [13]
We have to add the amounts:

4(2x+3y) + 3(5x+4)

First, though, we have to distribute:

4*2x + 4*3y + 3*5x + 3*4
8x + 12y + 15x + 12

Now we just need to simplify:

23x + 12y + 12

The  students planted 23x + 12y + 12 trees total.
7 0
4 years ago
Reference attached image for the problem.Please show your work for finding the partial area.
-Dominant- [34]

To find the area of a sector of a circle use the next formula:

A=\frac{\theta}{360º}*\pi *r^2

As the given circle has a outside angle 90º (it is not part of the sector of the circle) subtract the 90º from 360º (total angle of a circle) to find the angle of the sector:

\theta=360º-90º=270º

Find the area of the sector with angle 270º:

\begin{gathered} A=\frac{270º}{360º}*3.14*(11in)\placeholder{⬚}^2 \\  \\ A=0.75*3.14*121in^2 \\  \\ A=284.955in^2 \end{gathered}Then, the approximate area of the given sector of a circle is 284.955 square inches
7 0
1 year ago
Write an equivalent fraction for the whole number 6?
Keith_Richards [23]
6*2 = 12
12/2 = 6

So, the answer could be 12/2
6 0
3 years ago
Find the missing parts of the triangle. Round to the nearest tenth when necessary or to the nearest minute as appropriate.
Katena32 [7]

Answer:

  • A) A = 27.3°, B = 56.1°, C = 96.6°

Step-by-step explanation:

<u>Use the Law of Cosines:</u>

  • A = arccos [(b² + c² - a²)/(2bc)] = arccos [(13.2² + 15.8² - 7.3²)/(2*13.2*15.8)] = 27.3°
  • B = arccos [(a² + c² - b²)/(2ac)] = arccos [(7.3² + 15.8² - 13.2²)/(2*7.3*15.8)] = 56.1°
  • C = 180° - (A + B) = 180° - (27.3° + 56.1°) = 96.6°

Correct choice is A.

3 0
3 years ago
G(x)=3x-4 find (gog) (x)
Anestetic [448]

Answer:

gog(x)=9x-16

Step-by-step explanation:

We are given g(x)=3x-4 and are asked to find (gog) (x)

gog(x)=g(g(x))

g(x)=3x-4

Hence

g(g(x))=g(3x-4)

=3(3x-4)-4

=9x-12-4

=9x-16

Hence

gog(x)=9x-16

5 0
3 years ago
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