Ask question

Ask question

All categories

3 years ago

10

The graph of y = |2x – 2| – 4 is shown.

2 answers:

Whitepunk [10]3 years ago

8 0

Hi there!

The correct answer is the first option - an x intercept of the graph is (0,3). If you take a look at the graph, you'll see that one line crosses the x axis at (0,3). Meaning that, this is one x axis.

Hope this helps!! :)

julia-pushkina [17]3 years ago

5 0

Answer:

A y-intercept of the graph is (0, –2).

Step-by-step explanation:

c

You might be interested in

What is the simplest form of square root 1,764

oee [108]

$\bf \sqrt{1764}~~ \begin{cases} 1764=&2\cdot 2\cdot 3\cdot 3\cdot 7\cdot 7\\ &2^2\cdot 3^2\cdot 7^2\\ &(2\cdot 3\cdot 7)^2\\ &42^2 \end{cases}\implies \sqrt{42^2}\implies 42$

3 0

3 years ago

What is the equation of the circle with center (5,-4) and containing the points (5,-2)

gtnhenbr [62]

Answer:

The equation of a circle is $(x-5)^2+(y+4)^2=4$ .

Step-by-step explanation:

-The equation of a circle is:

$(x-h)^2+(y-k)^2=r^2$ (where center is $(h,k)$ , the point $(x_{1},y_{1})$ and the radius known as $r$ ).

-Use the center (5,-4) and the point (5,-2) for the equation:

$(5-5)^2+(-2+4)^2=r^2$

-Solve the equation:

$(5-5)^2+(-2+4)^2=r^2$

$0 + (-2)^2=r^2$

$4 = r^2$

$\sqrt{4} = \sqrt{r^2}$

$2 = r$

-After you found the radius, use the center (5, -4) and radius 2 to get the equation of a circle:

$(x-5)^2+(y+4)^2=2^2$

-Then, after you have the equation, the radius needs to simplified by the exponent:

$(x-5)^2+(y+4)^2=4$

3 0

3 years ago

If a point P(–1, –1) is reflected across the line y = –2, what are the coordinates of its reflection image?

liraira [26]

Any choices? I think I know this.

7 0

2 years ago

When will corona end?

padilas [110]

Answer:We don’t know for sure but soon

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

The table below shows the grades for three students on five assignments. Student 1 Grades 77, 80, 100, 75, 82 84, 92, 80, 82, 85

puteri [66]

yoooou are gay gaygay

7 0

2 years ago