1) gradient of line = Δ y ÷ Δ x
= (5 -2) ÷ (3 - (-6))
= ¹/₃
using the point-slope form (y-y₁) = m(x-x₁)
using (3,5)
(y - 5) = ¹/₃ (x -3)
y - 5 = ¹/₃x - 1
⇒ <span> y = ¹/₃ x + 4 [OPTION D]
</span>2) y = 2x + 5 .... (1)
<span> </span>y = ¹/₂ x + 6 .... (2)
by substituting y in (1) for y in (2)
2x + 5 = ¹/₂ x + 6
³/₂ x = 1
x = ²/₃
by substituting found x (2)
y = ¹/₂ (²/₃) + 6
y = ¹⁹/₃
∴ common point is (²/₃ , ¹⁹/₃) thus answer is FALSE [OPTION B]
3) Yes [OPTION A]
This is because the both have a gradient of 5 and if they have the same gradient then that means that the two lines are parallel to each other.
4) No [OPTION B]
Two lines are perpendicular if their gradients multiply to give - 1 and as such one is the negative reciprocal of the other. Since both gradients are ¹/₂ then they are actually parallel and not perpendicular.
Answer:
D
Line segments are congruent due to the side-angle-side congruence postulate.
Step-by-step explanation:
DC is the perpendicular bisector of line AB, this mean that DC divides AB at 90 degrees into two equal parts at point E. Hence:
AE = BE
Also DE ≅ DE (reflexive property of congruence)
Also ∠AED = ∠BED = 90° (perpendicular bisector)
We can therefore say that triangle AED and triangle BED are congruent according to the side-angle-side congruence theorem. Therefore line AD = line BD
Answer:
nice avatar and the answer is a
i
Answer:
1. 16 teachers 2. 8 tutor 3. 6 teachers
Step-by-step explanation:
It took the plane 1700 seconds for the plane to land. If you look at the x-axis, you can see that the x-intercept crosses through the point (0, 1700).
