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Dennis_Churaev [7]
3 years ago
13

What is greater 0.7 or 3/5

Mathematics
2 answers:
steposvetlana [31]3 years ago
4 0
The answer would be 0.7 since we can say that 3/5 of 100 makes 60 while 0.7 is 70 which means that 0.7 has more.
IRINA_888 [86]3 years ago
4 0
To compare the two, you either have to convert both to decimals or both to fractions. 

To convert 0.7 to a fraction, remember that 0.7 is 7/10. To compare 7/10 to 3/5, they must have the same denominator. 3/5 * 2/2 (since 2/2 is basically 1 and anything times 1 equals itself) = 6/10. Since 7/10 > 6/10, 0.7 is greater.

To convert 3/5 to a decimal, remember that 3/5 = 6/10 (what we did in the last part). 6/10 = 0.6. Since 0.7 > 0.6, that means 0.7 is greater than 3/5.

Your answer is 0.7 is greater.
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Step-by-step explanation:

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ahrayia [7]

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If we divide both sides by \frac{\sigma}{\sqrt{n}} we got:

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And we can use the normal distribution table or excel to find the probabilites and we got:

P(-1.5 \leq Z \leq 1.5)= P(ZStep-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

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X \sim N(M,4)  

Where \mu=M and \sigma=4

We select a a sample of n =4 and since the distribution for X is normal then we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And we want to find this probability:

P(-2 \leq \bar X -\mu \leq 2)

If we divide both sides by \frac{\sigma}{\sqrt{n}} we got:

P(\frac{-2}{\frac{4}{\sqrt{9}}}\leq Z \leq \frac{2}{\frac{4}{\sqrt{9}}})

And we can use the normal distribution table or excel to find the probabilites and we got:

P(-1.5 \leq Z \leq 1.5)= P(Z

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dmitriy555 [2]

Answer:

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Step-by-step explanation:

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