Jessica has 20 pieces of candy in a bag: 2 mint sticks, 9 jelly treats, and 9 fruit tart chews. If she eats one piece every 10 m inutes, what is the probability her first two pieces will both be jelly treats?
2 answers:
Answer:
18/95
Step-by-step explanation:
Given data
2 mint sticks,
9 jelly treats, and
9 fruit tart chews.
Sample space = {2+9+9} = 20
N/B this is done without replacement since the candy are eaten Hence after each selection the candy and the sample size reduces
1.The probability of eating the first jelly treat = 9/20
2.The probability of eating the first jelly treat = 8/19
Hence the probability of her first two pieces will both
be jelly i= 9/20*8/19= 72/380
= 18/95
Answer:
18.95%
Step-by-step explanation:
In this case what we must do is calculate the probability of eating a jelly treats first and then another jelly treats, being the final probability the multiplication of these events.
We know that there are 20 in total and that initially there are 9 jelly treats, so the first event is the probability:
9/20
And the second event, with one less in each, would be:
8/19
The final probability then:
9/20 * 8/19 = 0.1895
So the probability of this happening is 18.95%
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