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lapo4ka [179]
4 years ago
6

Jessica has 20 pieces of candy in a bag: 2 mint sticks, 9 jelly treats, and 9 fruit tart chews. If she eats one piece every 10 m

inutes, what is the probability her first two pieces will both be jelly treats?
Mathematics
2 answers:
blondinia [14]4 years ago
6 0

Answer:

18/95

Step-by-step explanation:

Given data

2 mint sticks,

9 jelly treats, and

9 fruit tart chews.

Sample space = {2+9+9} = 20

N/B this is done without replacement since the candy are eaten Hence after each selection the candy and the sample size reduces

1.The probability of eating the first jelly treat = 9/20

2.The probability of eating the first jelly treat = 8/19

Hence the probability of her first two pieces will both

be jelly i= 9/20*8/19= 72/380

= 18/95

dedylja [7]4 years ago
4 0

Answer:

18.95%

Step-by-step explanation:

In this case what we must do is calculate the probability of eating a jelly treats first and then another jelly treats, being the final probability the multiplication of these events.

We know that there are 20 in total and that initially there are 9 jelly treats, so the first event is the probability:

9/20  

And the second event, with one less in each, would be:

8/19

The final probability then:

9/20 * 8/19 = 0.1895

So the probability of this happening is 18.95%

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