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kobusy [5.1K]
2 years ago
8

Please help with these algebra questions!!!! I will give brainliest

Mathematics
1 answer:
vitfil [10]2 years ago
3 0

Answer:

the answer is negative numbers for 6

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Use the value of the first integral I to evaluate the two given integrals. I = integral^3_0 (x^3 - 4x)dx = 9/4 A. integral^3_0 (
Troyanec [42]

Answer:

A) -9/2

B) 9/4

C) -9/2, same as A)

Step-by-step explanation:

We are given that I=\int_0^3 x^3-4x dx=9/4. We use the properties of integrals to write the new integrals in terms of I.

A) \int_0^3 8x-2x^3 dx=\int_0^3 -2(x^3-4x) dx=-2\int_0^3 x^3-4x dx=-2I=-9/2. We have used that ∫cf dx=c∫f dx.

B) \int_3^0 4x - x^3 dx=-\int_0^3 (4x-x^3) dx=\int_0^3-(4x-x^3) dx=\int_0^3 x^3-4x dx=I=9/4. Here we used that reversing the limits of integration changes the sign of the integral.

C) It's the same integral in A)

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Ulani is constructing a triangle that has sides measuring 12 cm and 28 cm. Which measurements could be the length of the third s
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The answer is 24 cm and 38 cm
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The last statement is true
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altogether is 9

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