Answer:
-2x-5y+8z+4.5=0
Step-by-step explanation:
Let (x,y,z) be the coordinates of the point lying on the needed plane. This point is equidistant from the points (-3, 5, -4) and (-5, 0, 4), so

Answer:
c. 18
Step-by-step explanation:
First, you would find the total sum of the 60 numbers. The average is always the sum of the numbers divided by the number of numbers.
35*18=630
15*10=150
Now we do not know how many numbers the last group has. However, we can find it out doing 60-35-15 to see how many numbers are left. There would be 10 numbers left
10*30=300
630+150+300=1080
1080/60=18
Hence, the answer is C(18)
There are 3 girls .
9 students , 3 boys & 3 girls + another 3 boys because there are 3 more than girls so there are only 3 girls since you can't exceed 9 .
I am not sure! What is the original equation?
We have that
<span>A(-6,-5) and B (4,0)
we know that
</span><span>AP:PB is 2:3
so
(2+3)=5
AP=2/5
PB=3/5
step 1
find the x coordinate of P
Px=Ax+AP*ABx
where
Ax is the x coordinate of A
AP is 2/5
ABx is the distance AB in the x coordinate
so
PX=[-6+(2/5)*(4+6)]------>Px=-2
</span>step 2
find the y coordinate of P
Py=Ay+AP*ABy
where
Ay is the y coordinate of A
AP is 2/5
ABy is the distance AB in the y coordinate
so
Py=[-5+(2/5)*(0+5)]------>Py=-3
the point P is (-2,-3)
see the attached figure