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Elina [12.6K]
3 years ago
5

alice planted 6 tomato plants 4 bean plants and 2 pepper plant. each row had 6 plants. how many rows did she plant

Mathematics
2 answers:
ANTONII [103]3 years ago
6 0
First, add the number of plants.

6+4+2= 12 plants in total

There can be 6 plants in each row so divide 12 by 6 to get the number of rows used to plant 12 plants.

12/6=2

The answer is 2 rows. 
ehidna [41]3 years ago
3 0
Alice planted 12 :D

HAVE A NICE DAY OR NIGHT
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Order 0.709, 0.710, 0.79, and 0.079 from smallest to largest.
TEA [102]
0.079, 0.709, 0.710, 0.79


You will have to look at the placement of each digit.

In this case, after the decimal point:
tenths is the largest (the number directly to the right of the decimal point)
hundredths is next (the number directly to the right of the tenths place)
thousands is the smallest (in this case, next to the hundreds place)

hope this helps
3 0
3 years ago
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In the problem 8^3 - 10 × 5 - 4
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Answer: 458

<u>Simplify</u>

8³=8×8×8

<u>Multiply</u>

8×8×8=512

10×5=50

<u>Subtract</u>

512-50=462

462-4=458

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3 years ago
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Change 5 into a mixed number
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6 0
3 years ago
How can you use 2, 3, 5 and 8 to get 104?
Tamiku [17]
Salma showed me how to do it.

Here are two ways:

8 times (5·3 - 2)  =  8 times (15 - 2)  =  8 times 13  =  104 .

8 times (5·2 + 3)  =  8 times (10 + 3)  =  8 times 13  =  104.

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3 years ago
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A bridge spans a distance of 1012m. Large cables are attached to the tops of the towers, 45 m above the road. The road is suspen
Dovator [93]

Answer:

A quadratic equation for the large cables is f(x) = \dfrac{87 }{512072} \cdot x^2 + 1.5

Step-by-step explanation:

The shape of the quadratic equation representing the large cables is a parabola

Taking the point of the smallest vertical cables as the vertex, (h, k) with coordinates, (0, 1.5), we have;

h = -b/(2·a)

∴ 0 = -b/(2·a), from which we have, b = 2·a × 0 = 0

k = 1.5 = c - (b²/(4·a) = c - (0/(4·a)) = c

∴ c = 1.5

The standard form of the quadratic equation, a·(x - h)² + k is therefore, given as follows;

f(x) = a·(x - 0)² + 1.5 = a·x² + 1.5

At the towers which are on either side of the bridge, when x = 1012/2 = 506, f(x) = y = 45

Therefore, we have;

45 = a·506² + 1.5

a = (45 - 1.5)/506² = 87/512072 ≈ 1.699 × 10⁻⁴

The quadratic equation for the large cables, f(x), can therefore be presented as follows;

f(x) = \dfrac{87 }{512072} \cdot x^2 + 1.5

3 0
3 years ago
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