Ask question

Ask question

All categories

3 years ago

12

Taylor says ABCD and EFGH are congruent because he can map ABCD to EFGH by multiplying each side length by 1.5 and translating t

he result to coincide with EFGH. What is Taylor's error?

1 answer:

Elina [12.6K]3 years ago

8 0

Answer:

The E came before H

Step-by-step explanation:

You might be interested in

If the point (3,-4) is dilated by a scale factor of 74 , what are the new coordinates?

Delvig [45]

Answer:

(-222, 296)

Step-by-step explanation:

<u>Given point </u>

(3, -4)

<u>Dilation by a scale factor of 74:</u>

(x, y) → (74x, 74y)
(3, -4) → (74*3, 74(-4)) = (222, -296)

<u>Rotation by 180°:</u>

(x, y) → (-x, -y)
(222, -296) → (-222, 296)

8 0

3 years ago

The hypotenuse of the right triangle is 5y inches long. The lengths of the legs are x + 8 and x + 3 inches. If the perimeter of

Nata [24]

Answer:

25

Step-by-step explanation:

The perimeter of triangle is equal to the sum of all sides of triangle

then:

5y + (x+8) + (x+3) = 60

5y + 2x +11 = 60

5y +2x = 49 ..............................................................(1)

the hypotenuse - shorter leg = 10

hint ( shorter leg ) = x+3

then

5y - (x + 3 ) = 10

5y - x - 3 = 10

5y - x = 13 .................................................... (2)

from 1 and 2

5y +2x = 49 .................................................................. (3)

5y - x = 13 (multiply both sides by 2 )

10y - 2x = 26 ..................................................................(4)

by sum 3 and 4

15y = 75

then y = 75/15 = 5

then hypotenuse = 5y = 5 x 5 = 25

6 0

3 years ago

1. Simplify -7 + {12 - 3[50 - 4(2+3)] }

Komok [63]

1. Simplify $-7 + (12 - 3[50 - 4(2+3)])$ this expression step by step:

$2+3=5;$
$4\cdot (2+3)=4\cdot 5=20;$
$50-4\cdot (2+3)=50-20=30;$
$3\cdot [50-4(2+3)]=3\cdot 30=90;$
$12-3\cdot[50-4(2+3)]=12-90=-78;$
$-7 + (12 - 3[50 - 4(2+3)])=-7+(-78)=-7-78=-85.$

2. Simplify the expression $\dfrac{1}{3} + 6\left(\dfrac{2}{3} - \dfrac{1}{6}\right)^2$ in the same way:

$\dfrac{2}{3}-\dfrac{1}{6}=\dfrac{2\cdot 2-1}{6}=\dfrac{3}{6}=\dfrac{1}{2}$
$\left(\dfrac{2}{3} - \dfrac{1}{6}\right)^2=\left(\dfrac{1}{2} \right)^2=\dfrac{1}{4}$
$\dfrac{1}{3} + 6\left(\dfrac{2}{3} - \dfrac{1}{6}\right)^2=\dfrac{1}{3} + 6\cdot \dfrac{1}{4}=\dfrac{1}{3}+\dfrac{3}{2}=\dfrac{1\cdot 2+3\cdot 3}{6}=\dfrac{11}{6}$

6 0

4 years ago

What is the square root of 8

miss Akunina [59]

Answer:

2.82842712475

Step-by-step explanation:

did this help you

4 0

4 years ago

Read 2 more answers

How are we supposed to solve this question!?

VashaNatasha [74]

Answer:

use pythagorean's theorem; x=6

Step-by-step explanation:

a^2 + b^2 = c^2

a=length; b(x)=height; c= hypotenuse (longest side)

8^2 + b^2 = 10^2

64 + b^2 = 100 (subtract 64 from each side)

b^2= 36

6 x 6 = 36 so b=6

x=6

6 0

3 years ago

Read 2 more answers