Question

Jefferson High School is looking to expand its student parking lot by expanding the existing lot as

Answer 1

brainly.com/question/3577543

This was already answered.

Answer 2

Answer:

The value of x is 60 ft.

Step-by-step explanation:

The area of a rectangle is

$A=length \times width$

The area of school is

$A=165\times 300=49500$

The area of old lot with school is

$A=(165+75)(300+75)=90000$

The area of old lot without school is

$A_1=90000-49500=40500$

The area of new lot with school is

$A=(165+75+x)(300+75+x)=x^2 + 615 x + 90000$

The area of old lot without school is

$A_2=x^2 + 615 x + 90000-49500=x^2 + 615 x + 40500$

It is given that the area of new parking lot will be twice the size of the old parking lot.

$2A_1=A_2$

$2(40500)=x^2 + 615 x + 40500$

$0=x^2 + 615 x -40500$

$0 = (x - 60) (x + 675)$

$x=60,-675$

The value of x can not be negative. Therefore the value of x is 60 ft.