Answer:
approximate 23.590 feet
Step-by-step explanation:
tan 65° = x / 11 = 2.145
x = 11 x 2.145 = 23.595
Answer:
$8
Step-by-step explanation:
After the shoe purchase, her balance was $50 -45 = $5.
After depositing her babysitting earnings, her balance was $5+25 = $30.
After buying pizza, her balance was $30 -42 = -$12.
<em>Assuming no overdraft charge</em>, her balance after depositing her earnings was ...
-$12 +20 = $8
Sally's balance on Sunday was $8.
Answer:
The correct answer is 12.8 J.
Step-by-step explanation:
To solve this problem, we must remember how to calculate the kinetic energy of an object.
The kinetic energy is represented by the formula K = 1/2 * m * v^2, where m represents the mass of the object and v represents the speed or velocity of the object. If we plug in the given values into the formula, we get:
K = 1/2 * m * v^2
K = (1/2) * (0.40) * (8.0)^2
Our first step is to square the velocity. After doing this step, we get the following:
K = (1/2) * (0.40) * (64)
Finally, we can perform the multiplication, to get:
K = 12.8
The unit for kinetic energy is joules, so the correct answer is 12.8 J.
Hope this helps!
Answer:
The standard deviation of a probability distribution is a measure of variability of the distribution.
Step-by-step explanation:
We have been given an incomplete statement. We are asked to complete the given statement.
We know that standard deviation is measure of variability or dispersion of a set of data values.
It tells up how much a data point is spread out from the average or mean of the data set.
Therefore, option A is the correct choice.
Answer: Margin of error = 6.58
Confidence interval = (26.91, 40.08)
Step-by-step explanation:
Since we have given that
Sample size n = 8
Sample mean = 33.5 minutes
Population standard deviation = 9.5 minutes
At 95% confidence interval,
α = 0.05
t = 1.96
So, Margin of error is given by

Confidence interval would be
Lower limit:

Upper limit:

Hence, the interval would be (26.91, 40.08)
But at standard deviation 7.2 minutes, the confidence interval was (27.5, 39.5)
Confidence interval using the standard normal distribution is wider than the confidence interval using t distribution.