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algol13
3 years ago
11

1 subscription for $21, 28 subscriptions for x dollars help please

Mathematics
2 answers:
Black_prince [1.1K]3 years ago
7 0

Answer:

Just do 28*21 which is 588$

Step-by-step explanation:

PLEASE MARK BRAINLIEST

zepelin [54]3 years ago
5 0

Answer:

please mark other person brainliest

Step-by-step explanation:

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What is 265409 rounded to the nearest hundred thousand
zubka84 [21]
The answer to your question is 300,000
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4 years ago
Cuanto es 1 1/4 + 1/2 + 3 1/2 =?<br> Ayudaaa
likoan [24]

Answer:

es 1 1/4 + 2/4 +3 2/4 = 5 1/4

5 1/4

6 0
1 year ago
What is the Y intercept of the line described for the equation below?y=4x-9
Vladimir [108]

Answer: Assuming that it's already in the standard form - y=mx+b | Your Y-Intercept is going to be -9


Step-by-step explanation:

Using the equation y=mx+b, anything that is in place of the (b) is your Y-Intercept and your slope is (m)

8 0
3 years ago
Read 2 more answers
Cuánto le falta a 1/4 para llegar a 4/5​
german

Answer:

4/5 - 1/4

Step-by-step explanation:

4/5 =0.8

1/4=0.25

  ⇒0.8 - 0.25 = 0.55 (decimal form)

  ⇒4/5 - 1/4 = 11/20 (exact form-fraction)

6 0
3 years ago
IN A CLASS OF 60 STUDENTS, 25 PLAYS BASKETBALL, 2O PLAY VOLLEYBALL, AND 10 STUDENTS PLAY BOTH OF THEM. HOW MANY STUDENTS PLAY NE
I am Lyosha [343]

Answer:

25

Step-by-step explanation:

We'll compare it with the study of sets, the most noticeable operation of which is:

  • <u>n(A ∪ B) = n(A) + n(B) - n(A ∩ B)</u>

where,

n(A ∪ B) is the Union Set, i. e, the set that contains all the elements

n(A) is a subset of the Union Set

n(B) is another subset of the Union Set, and

n(A ∩ B) is the Intersection Set ,i.e, the set contains common elements from both A and B sets.

<h3><u>In the question:</u></h3>
  • n(A ∪ B) = ? (<em>the total number of students in the class who are into the above mentioned sports)</em>

Let set A contains the students who play basketball and set B, the students who play Volleyball.

  • n(A) = 25
  • n(B) = 20

10 students play both of them, i. e.,

  • n(A ∩ B) = 10 (<em>as 10 students have common sports - Volleyball and Basketball</em>)

<u>Using the above operation:</u>

=> n(A ∪ B) = n(A) + n(B) - n(A ∩ B)

=> n(A ∪ B) = 25 + 20 - 10

=> n(A ∪ B) = 35

<h3><u>Final Step to the Answer:</u></h3>

<u>The total number of students in the class </u>

= students into the given sports + students who don't play any of them

  • Total number of students in the class is 60
  • Total number fo students playing basketball and volleyball is 35

The students who play neither = 60 - 35

= 25

5 0
3 years ago
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