j=4.88 when g=8 and v=11
Further explanation:
When the increase/decrease in one quantity cause increase/decrease in other quantity, it is called direct variation.
Variation is always accompanied by a variation constant.
<u>Given</u>
g and v vary directly with j
IT can be written as:
j∝gv
Putting the variation constant k
j = kgv
Putting g = 6 and v=3
![j = kgv\\1 = k * 6 * 3\\1 = 18k\\k = \frac{1}{18}](https://tex.z-dn.net/?f=j%20%3D%20kgv%5C%5C1%20%3D%20k%20%2A%206%20%2A%203%5C%5C1%20%3D%2018k%5C%5Ck%20%3D%20%5Cfrac%7B1%7D%7B18%7D)
So the value of k is 1/18 which makes the equation
![j = \frac{1}{18}gv\\ Putting\ g=8\ and\ v=11\\j = \frac{1}{18} * 8 * 11\\j = \frac{88}{18}\\ j =4.88](https://tex.z-dn.net/?f=j%20%3D%20%5Cfrac%7B1%7D%7B18%7Dgv%5C%5C%20Putting%5C%20g%3D8%5C%20and%5C%20v%3D11%5C%5Cj%20%3D%20%5Cfrac%7B1%7D%7B18%7D%20%2A%208%20%2A%2011%5C%5Cj%20%3D%20%5Cfrac%7B88%7D%7B18%7D%5C%5C%20j%20%3D4.88)
So, j=4.88 when g=8 and v=11
Keywords: Variation, Direct Variation
Learn more about variation at:
#LearnwithBrainly
Answer:
1594323
Step-by-step explanation:
Answer:
The loose sweets at ?0.89 for 100 g.
Step-by-step explanation:
First, calculate the price per gram. You do this by dividing the price by the grams.
?1.49 / 120 g = 1.49 / 120 = 0.0124 (4 dp)
Because the answer was very long, I have rounded it to 4 decimal places (4 dp).
?0.89 / 100 g = 0.89 / 100 = 0.0089
Next, you must calculate both pre-packed and loose sweets to the same weight. I am calculating them both to 100 g.
0.0124 x 100 = 1.24
0.0089 x 100 = 0.89
Finally, the cheapest product for 100 g will be the better value. In this case, it is the loose sweets.
<span>
</span><span>http://www.squiglysplayhouse.com/BrainTeasers/bt.php?id=119
this should help</span>